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29 Nov 2015, 11:19
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (01:54) correct
22%
(02:16)
wrong
based on 3369
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In the formula \(w = \frac{p}{\sqrt[t]{v}}\), integers p and t are positive constants. If w = 2 when v = 1 and if w = 1/2 when v = 64, then t =
(A) 1
(B) 2
(C) 3
(D) 4
(E) 16
PS30502.01
(A) 1
(B) 2
(C) 3
(D) 4
(E) 16
PS30502.01
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30 Sep 2020, 10:55
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Bunuel
1. We are given \(w = \frac{p}{\sqrt[t]{v}}\)
2. Substituting \(v = 1\) and \(w = 2\) in \(w = \frac{p}{\sqrt[t]{v}}\) -> \(2 = \frac{p}{\sqrt[t]{1}}\) -> \(p = 2\)
3. Substituting \(p = 2\), \(v = 64\) and \(w = \frac{1}{2}\) in \(w = \frac{p}{\sqrt[t]{v}}\) -> \(\frac{1}{2} = \frac{2}{\sqrt[t]{64}}\) -> \(\frac{1}{2} = \frac{2}{2^{6/t}}\) -> \(2^{\frac{6}{t}} = 2^2\) -> \(\frac{6}{t} = 2\) -> \(t = 3\)
Ans C
24 Oct 2020, 06:36
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We're given: \(w = \frac{p}{\sqrt[t]{v}}\)
We're told w = 2 when v = 1 and w = 1/2 when v = 64.
Lets plug these numbers in:
\(2 = \frac{p}{\sqrt[t]{1}}\)
We know p must equal 2, as the root of 1 is 1.
Lets plug w = 1/2 in:
\(0.5 = \frac{2}{\sqrt[t]{64}}\)
To get 0.5, t must be 3.
Answer is C.
We're told w = 2 when v = 1 and w = 1/2 when v = 64.
Lets plug these numbers in:
\(2 = \frac{p}{\sqrt[t]{1}}\)
We know p must equal 2, as the root of 1 is 1.
Lets plug w = 1/2 in:
\(0.5 = \frac{2}{\sqrt[t]{64}}\)
To get 0.5, t must be 3.
Answer is C.
