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nakib77
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Q 4. If n is the product of the integers from1 to 20 13 Oct 2005, 13:51
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Q 4.
If n is the product of the integers from1 to 20 inclusive, what is the greatest integer k for which 2k is a factor of n?
A. 10
B. 12
C. 15
D. 18
E. 20



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Q 4. If n is the product of the integers from1 to 20 13 Oct 2005, 14:21
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D.

1 * 2 * 3 * 4 *....*9*...*19*20

is divisible by: 36
k = 18
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Q 4. If n is the product of the integers from1 to 20 13 Oct 2005, 14:25
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E

1*4*...*10*...*20 is divisible by 40 = 2k. So K=20
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sudhagar
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Q 4. If n is the product of the integers from1 to 20 13 Oct 2005, 14:59
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Answer should be E

Duttsit: I think you took only 19 & 20 into consideration. You can take any even and 20 we should be able to get 2 * 20 as factor.

Actually all the below are factors and we need to get only the 'greatest'
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Q 4. If n is the product of the integers from1 to 20 14 Oct 2005, 14:21
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But OA is D.
Can somebody explain that. or is it OA is wrong?
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sudhagar
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Q 4. If n is the product of the integers from1 to 20 14 Oct 2005, 14:54
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Duttsit is the person who got the answer D.

Duttsit: Could you please help?
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Q 4. If n is the product of the integers from1 to 20 14 Oct 2005, 15:30
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nakib77
But OA is D.
Can somebody explain that. or is it OA is wrong?
Show more


OA probably wrong, where is this question from?
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HongHu
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Q 4. If n is the product of the integers from1 to 20 14 Oct 2005, 17:58
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Is the question correct? I mean n is a factor of n itself right? So n/2 would be the biggest k (since we know n is even and thus n/2 is an integer). In other words k would be 20!/2. The question may be asking about k as a product of prime numbers or something ...
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Q 4. If n is the product of the integers from1 to 20 14 Oct 2005, 19:10
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Oh I get it the question is asking

2^k is a factor of N

so then
lets see...

20/2=10

then you get another 2 from 4, you get 2 2s from 8, 12, you get another 2, from 16 you get 3 2s... and one more 2 from 20, so lets count all the 2s then

10+1+2+1+3+1=18

K can be 18....D it is...
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Q 4. If n is the product of the integers from1 to 20 14 Oct 2005, 21:13
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To be more clear ... Since we are asked 2 power of k, lets take only multiples of 2.

2 * 4 * 6 * 8 ... * 20

2, 6, 10, 14, 18 = 2^1 * odd (2^1 occurs 5 times)
4, 12, 20 = 2^2 * odd (2^2 occurs 3 times)
8 = 2^3
16 = 2^4

5 * 1 + 3 * 2 + 3 + 4 = 18. Hence D.
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Q 4. If n is the product of the integers from1 to 20 15 Oct 2005, 06:04
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Thank you. I didn't see that exponent. :arh I was so mad while I was solving it.

this question is from paper based question from ETS.



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