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P(two six) = P(six on die 1) * P(six on die 2) = 1/36
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sudhagar
After the LuckyAir flight arrived in Las Vegas, John went to
the strip to gamble. At the craps table, John bet $20 on
boxcars (two sixes). If John rolls two fair, six-sided dice,
what is the probability that he will roll two sixes?

A. 2/12
B. 1/8
C. 1/2
D. 1/24
E. 1/36


These are independent events. So it is the product of each of the probablities.

Hence it is (1/6) * (1/6) = 1/36



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