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After the LuckyAir flight arrived in Las Vegas, John went to

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sudhagar
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After the LuckyAir flight arrived in Las Vegas, John went to [#permalink] New post   19 Oct 2005, 13:09
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After the LuckyAir flight arrived in Las Vegas, John went to
the strip to gamble. At the craps table, John bet $20 on
boxcars (two sixes). If John rolls two fair, six-sided dice,
what is the probability that he will roll two sixes?

A. 2/12
B. 1/8
C. 1/2
D. 1/24
E. 1/36



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Re: After the LuckyAir flight arrived in Las Vegas, John went to [#permalink] New post   19 Oct 2005, 14:46
Probability of rolling a 6 on the 1st dice = 1/6
Probability of rolling a 6 on the 2nd dice = 1/6

Since these are not OR probabilities, meaning they both have to occur, you mulitply them.

1/6 * 1/6 = 1/36
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Re: After the LuckyAir flight arrived in Las Vegas, John went to [#permalink] New post   19 Oct 2005, 18:53
OA is E.

Here is the detailed explanation:
If two events are independent, the probability of both events occurring is the product of the two individual probabilities. The rolling of each die is an independent event. The outcome of one die does not affect the outcome of the other.

The probability of an event occurring is the number of possible outcomes for the event divided by the total number of possible outcomes. Their is only one outcome out of six that will produce a six when you roll a die. Thus, the probability of one die rolling a six is 1/6.

The probability of rolling two sixes is (1/6)*(1/6) or 1/36.
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Re: After the LuckyAir flight arrived in Las Vegas, John went to [#permalink] New post   19 Oct 2005, 19:04
P(two six) = P(six on die 1) * P(six on die 2) = 1/36
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Re: After the LuckyAir flight arrived in Las Vegas, John went to [#permalink] New post   19 Oct 2005, 21:56
sudhagar wrote:
After the LuckyAir flight arrived in Las Vegas, John went to
the strip to gamble. At the craps table, John bet $20 on
boxcars (two sixes). If John rolls two fair, six-sided dice,
what is the probability that he will roll two sixes?

A. 2/12
B. 1/8
C. 1/2
D. 1/24
E. 1/36


These are independent events. So it is the product of each of the probablities.

Hence it is (1/6) * (1/6) = 1/36



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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Re: After the LuckyAir flight arrived in Las Vegas, John went to [#permalink]
19 Oct 2005, 21:56
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