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Bunuel
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sarajkluz
My solution:

1st (r=2)
pi(r)^2=3.14(4)
pi(r)^2= 12.56

2nd (r=2.2)
pi(r)^2=3.14(4.84)
pi(r)^2=15.20

Calculate change
15.20-12.56=2.64
2.64/12.56=21%


*looking for feedback. I subbed in value 5 too for r and got 20% in the end....

If r=5 Area= pi*25
If r=5*(1.10)=5.5 Area= pi*30.25
So 30.25/25 -1= 0.21= 21%

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Let's take radius (r) = 10

According to the formula πr^2

Original area of a circle be 100π
Now, the new Radius is increased by 10% I.e.
New radius (R) = r+ (10% of r)
R = 10 + (0.1*10) = 10+(1) =
R=11
now

we have new area (bigger one) = 121π


Change in area =
{(new area- original area)/100π (original) } *100%
(121π-100π)/100π*100%

Which is 21% .. option B

I hope it was clear with this detailed description

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Bunuel
If the radius of a circle is increased by 10%, by how much is its area increased?

A. 25%
B. 21%
C. 20%
D. 15%
E. 10%


Radius be 10 and 10% increased will be 11

So pi*10^2, 100 *pi and pi*11^2= 121* pi
21/100= 21% option B
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Bunuel
If the radius of a circle is increased by 10%, by how much is its area increased?

A. 25%
B. 21%
C. 20%
D. 15%
E. 10%

Asked: If the radius of a circle is increased by 10%, by how much is its area increased?

Area = \(\pi r^2\)

New Area = \(\pi (1.1r)^2 = 1.21 \pi r^2 = (1 + .21) \pi r^2 \)

IMO B
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