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09 Jan 2017, 06:57
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B
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Difficulty:
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69% (01:55) correct
31%
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In a bowl of marbles, 8 are yellow, 6 are blue, and 4 are black. If Michelle picks 2 marbles out of the bowl at random and at the same time, what is the probability that at least one of the marbles will be yellow?
(A) 5/17
(B) 12/17
(C) 25/81
(D) 56/81
(E) 4/9
(A) 5/17
(B) 12/17
(C) 25/81
(D) 56/81
(E) 4/9
09 Jan 2017, 08:02
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Bunuel
P(no yellow) = \(\frac{10C2}{18C2} =\frac{5}{17}\)
P(at least 1 yellow) = \(1 - \frac{5}{17} = \frac{12}{17}\)
B.
09 Jan 2017, 08:24
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There is 18 marbles in total
It's more easier to start with the probability to pick none of the yellow marbles => 10/18 * 9/17 = 5/17
The probability to pick up at least one yellow marble (1- the prob to have none) will be 1 - 5/17 = 12/17 => B
It's more easier to start with the probability to pick none of the yellow marbles => 10/18 * 9/17 = 5/17
The probability to pick up at least one yellow marble (1- the prob to have none) will be 1 - 5/17 = 12/17 => B
