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gamjatang
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GMATT73
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Quote:
I`ve been staring at this problem for over 10 minutes. What the heck is it asking?


Maybe the intention was for you to do just that! :wink:
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strange
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GMATT73
I`ve been staring at this problem for over 10 minutes. What the heck is it asking?


If the fruit weighing 100 gms has 99% water, when the water content is 98%, the weight should be about 99 gms.. unless the question has more components to determine what else gets effected by drying.
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GMATT73
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yb
Quote:
I`ve been staring at this problem for over 10 minutes. What the heck is it asking?

Maybe the intention was for you to do just that! :wink:


That`s just plain cruel. :angry
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gamjatang
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Sorry guys. Forgive me of my poor english. :-(

The OA is 50g.

-----------------------------------------------------------------
Before getting dried, the weight of the fruit is 100 gram.
Since 99% of it is water, the portion which is not water is 1 gram.

After getting dried, 98% of the fruit is water.

Now, let x be the weight of water and T be the weight of the fruit.
(T = x + 1)

(x/T) * 100 = 98%
100x = 98T
100x = 98(x + 1)
2x = 98
x = 49

T = 49 + 1 = 50
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50...(90-x)/(100-x)=98/100...solve for x !
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Very good brain teaser, gamjatang. Thank you. Nice one



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