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17 Jul 2017, 13:44
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
100% (02:07) correct
0%
(00:00)
wrong
based on 2
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Not Attempted Yet
The least number which should be added to 28523 so that the sum is exactly divisible by 3, 5, 7 and 8 is
A. 41
B. 42
C. 32
D. 37
E. 45
kudo please if you liked the ques.
A. 41
B. 42
C. 32
D. 37
E. 45
kudo please if you liked the ques.
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17 Jul 2017, 15:16
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The question basically asks, when 28523 is divided by 8*7*5*3, a remainder will be there. Now what is the minimum number that should be added to 28523 so that it becomes completely divisible by 8*7*5*3.
8*7*5*3 = 840
Remainder when 28532 is divided by 840 = 803
So the minimum number to be added is 840-803 = 37
Answer is D
8*7*5*3 = 840
Remainder when 28532 is divided by 840 = 803
So the minimum number to be added is 840-803 = 37
Answer is D
17 Jul 2017, 16:53
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The approach above is great (though not something you'll likely need to use on a GMAT question). Alternatively, if we know 28523 + k is divisible by both 5 and 8, then it must be divisible by 40, so it must have a units digit of zero. If 28523 + k has a units digit of zero, and k is positive, then k must have a units digit of 7, so only answer D can be right. We don't actually need to use the fact that the sum is divisible by 3 or 7.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
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Thank you for understanding, and happy exploring!
