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Bunuel
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What's the Official solution for this?
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If the square of a number is the number itself then the only possible solutions are 0 or 1

We know, by av properties, that |a|^2 = a^2

Therefore;

|x - 2|^2 = (x - 2)^2

So we end with the following equation:

|x - 2|^2 = |x - 2|

The number |x - 2| has to be either 1 or 0 so:

|x - 2| = 0

x = 2

|x - 2| = 1

x = 1
x = 3

The roots are 1, 2 and 3, which product is 6
Ans E
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Deconstructing the Question

We are asked for the product of all roots of \((x - 2)^2 = |x - 2|\).

Let y = x - 2.

Then the equation becomes \(y^2 = |y|\).

Step-by-step

If \(y \ge 0\), then \(|y| = y\).

So \(y^2 = y\).

Thus,

\(y(y - 1) = 0\)

So \(y = 0\) or \(y = 1\).

If \(y < 0\), then \(|y| = -y\).

So \(y^2 = -y\).

Thus,

\(y(y + 1) = 0\)

So \(y = 0\) or \(y = -1\).

Only -1 works in this case.

Therefore, the solutions for \(y\) are

\(y = -1, 0, 1\)

Now convert back to \(x\):

\(x = y + 2\)

So,

\(x = 1, 2, 3\)

Their product is

\(1 \cdot 2 \cdot 3 = 6\)

Answer: E
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Here's a clean step-by-step solution:

The equation is (x - 2)2 = |x - 2|.

Step 1: Simplify with a substitution.
Let u = x - 2. The equation becomes:
u2 = |u|

Step 2: Rearrange.
u2 - |u| = 0
|u|(|u| - 1) = 0

(This works because u2 = |u|2, so we can factor out |u|.)

Step 3: Solve.
Either |u| = 0, which gives u = 0
Or |u| - 1 = 0, which gives |u| = 1, so u = 1 or u = -1

Step 4: Convert back to x (since u = x - 2):
- u = 0 → x = 2
- u = 1 → x = 3
- u = -1 → x = 1

Step 5: Find the product of all roots.
2 × 3 × 1 = 6

Answer: E

Key Insight: When you see the same expression on both sides of an equation (here, x - 2), substitute a single variable for it. This dramatically simplifies the algebra. Also, never divide both sides by a variable (like |u|) — you'd lose the u = 0 solution. Always factor instead.
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