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What's the Official solution for this?
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If the square of a number is the number itself then the only possible solutions are 0 or 1

We know, by av properties, that |a|^2 = a^2

Therefore;

|x - 2|^2 = (x - 2)^2

So we end with the following equation:

|x - 2|^2 = |x - 2|

The number |x - 2| has to be either 1 or 0 so:

|x - 2| = 0

x = 2

|x - 2| = 1

x = 1
x = 3

The roots are 1, 2 and 3, which product is 6
Ans E
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