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saswata4s
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5 integers, not necessarily distinct, are chosen from the integers 03 Jan 2018, 05:43
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5 integers, not necessarily distinct, are chosen from the integers between –(n+1) and n, inclusive, where n is a positive integer. If the probability that the product of the chosen integers is zero is 1 – (0.9375)^5, then what is the value of n?

A) 7
B) 8
C) 9
D) 15
E) 16



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mohdtaha
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5 integers, not necessarily distinct, are chosen from the integers 03 Jan 2018, 06:06
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saswata4s
5 integers, not necessarily distinct, are chosen from the integers between –(n+1) and n, inclusive, where n is a positive integer. If the probability that the product of the chosen integers is zero is 1 – (0.9375)^5, then what is the value of n?

A) 7
B) 8
C) 9
D) 15
E) 16
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15/16 is 0.9375. This means that the total number from -(n+1) to n inclusive equals 16. If 8 is the answer this means there are: (-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8) 18 numbers. Shouldn't the answer be 7?
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5 integers, not necessarily distinct, are chosen from the integers 03 Jan 2018, 06:18
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mohdtaha
saswata4s
5 integers, not necessarily distinct, are chosen from the integers between –(n+1) and n, inclusive, where n is a positive integer. If the probability that the product of the chosen integers is zero is 1 – (0.9375)^5, then what is the value of n?

A) 7
B) 8
C) 9
D) 15
E) 16

15/16 is 0.9375. This means that the total number from -(n+1) to n inclusive equals 16. If 8 is the answer this means there are: (-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8) 18 numbers. Shouldn't the answer be 7?
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Yes agree with mohdtaha

if -(n+1) & n are inclusive, then total terms in the series=n+(n+1)+1=2n+2

and as 2n+2=16=>n=7
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5 integers, not necessarily distinct, are chosen from the integers 03 Jan 2018, 06:51
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mohdtaha
saswata4s
5 integers, not necessarily distinct, are chosen from the integers between –(n+1) and n, inclusive, where n is a positive integer. If the probability that the product of the chosen integers is zero is 1 – (0.9375)^5, then what is the value of n?

A) 7
B) 8
C) 9
D) 15
E) 16

15/16 is 0.9375. This means that the total number from -(n+1) to n inclusive equals 16. If 8 is the answer this means there are: (-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8) 18 numbers. Shouldn't the answer be 7?

Yes agree with mohdtaha

if -(n+1) & n are inclusive, then total terms in the series=n+(n+1)+1=2n+2

and as 2n+2=16=>n=7
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why did u take 16


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5 integers, not necessarily distinct, are chosen from the integers 03 Jan 2018, 06:58
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riniglory
why did u take 16
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Hi riniglory,

Refer to the earlier solution posted by mohdtaha

Total number of integers is 16 which means -(n+1) to n has 16 terms.



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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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