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08 Jan 2018, 12:14
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Worker A takes 8 hours to do a Job, Worker B & C takes 6 hours do that same job and Worker A and C takes 4 Hours to do that same job.
How long does it take for Worker B to do it by himself?
Bit confused on this one for myself
How long does it take for Worker B to do it by himself?
Bit confused on this one for myself
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08 Jan 2018, 17:32
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A does 1/8 of the job per hour. A and c together to 1/4 of the job per hour.
C must also do 1/8 of the job per hour.
B and c do 1/6 of the job per hour and c does 1:8.
B must do the rest. 1/6-1/8=1/24.
B does 1/24 of the job per hour so it takes him 24 hours.
C must also do 1/8 of the job per hour.
B and c do 1/6 of the job per hour and c does 1:8.
B must do the rest. 1/6-1/8=1/24.
B does 1/24 of the job per hour so it takes him 24 hours.
08 Jan 2018, 23:04
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chaosfirestorm
--------------
Lets convert the problem statement into equations:
Worker A takes 8 hours to do a Job, => a= 8 (a is the time required for worker A to complete the job)
Worker B & C takes 6 hours do that same job
=> 1/b + 1/c = 6 --(1)
(where b & c are the hours required for worker b & C to complete the job if done individually)
and Worker A and C takes 4 Hours to do that same job
=> 1/a + 1/c = 1/4
since a=8
1/c = 1/8
Substituting the value of c in (1) - we get 1/b = 1/24
Thus, it takes 24 hours for Worker B to do it by himself
