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Bunuel
An empty cylindrical tank with a radius of 5 inches and a height of 10 inches is filled with water at a rate of 75 cubic feet per second. Approximately how many seconds will it take for the tank to be full?

A 8

B 9

C 11

D 13

E 15

Volume of the Cylindrical cube is \(π*5^2*10\)

Speed of water rushed into the tank is \(75 => 5^2*3\)

So time required is \(\frac{π*5^2*10}{5^2*3}=\frac{10π}{3} = \frac{10*22}{7*3}\)

Or, the time required is \(\frac{220}{21}\) ~ \(11\), Thus Answer must be (C) 11
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Abhishek009
Bunuel
An empty cylindrical tank with a radius of 5 inches and a height of 10 inches is filled with water at a rate of 75 cubic feet per second. Approximately how many seconds will it take for the tank to be full?

A 8

B 9

C 11

D 13

E 15

Volume of the Cylindrical cube is \(π*5^2*10\)

Speed of water rushed into the tank is \(75 => 5^2*3\)

So time required is \(\frac{π*5^2*10}{5^2*3}=\frac{10π}{3} = \frac{10*22}{7*3}\)

Or, the time required is \(\frac{220}{21}\) ~ \(11\), Thus Answer must be (C) 11

Abhishek009

If you see the flow rate is given in cubic feet per second / ft^3 ; where as the dimensions of the tank are given in inches... dont you think that we need to convert feet to inches or vice versa so as to get exact time rate .. I had asked Bunuel similar doubt I am yet to get his response..
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Bunuel :
There seems to be some disparity in the question with respect to units, So if unit conversion is not considered:

Work = Volume of cylinder = pi*r^2*h = 22/7 * 25 * 10
Rate = 75 cubic feet/sec
Time = Work/Rate = 22*25*20/7*75 ~ 11

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