A bus travels at a speed of 45 kmph. But it stops every 250 meters at

Question

A bus travels at a speed of 45 kmph. But it stops every 250 meters at a bus-stop for 1 minute. In how many minutes does the bus cover a distance of 6 kms.

A. 8
B. 30
C. 31
D. 32
E. None of these

av1901 · Answer

Bus travels at 45kmph
=> 45 km in 1 hour
=> 1 km in  \frac{1}{45} hours

Let us convert hours to minutes now by multiplying the hour with 60

=> 1 km in  \frac{4}{3} minutes

=> 0.25 km in  \frac{1}{3} minutes

So the bus takes  \frac{1}{3}  minutes to reach 250m and then stops for 1 minute

So, for every 250m, time taken =  1 + \frac{1}{3} = \frac{4}{3} minutes

And 1 km means repeating the 250m part four times =  \frac{4}{3}*4 = 16/3

Now the bus rides 6km in total so if we took the above time for 1km, for 6km, we multiply the above result by 6

=  \frac{16}{3}*6 = 32

We need to find time taken by bus to cover 6km

But with the above we have taken into consideration and added AN EXTRA MINUTE for when the bus stops for a minute after reaching the 6km mark because bus stops after every 250m

We have to subtract this because once the bus reaches 6km, our goal it to find that time, not to include stoppage after that

So, time =  32 - 1 = 31

Answer - C

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sanjitscorps18 · Answer

The bus travels at 45kmph
In one minute the bus travels = 45/60 km/min = 3/4km = 750 m
Hence the bus travels 250 m in 20 seconds

Now for the 1st km, the bus stops 3 times (once at 250m, 500m, and 750m each).
Total time taken (in seconds) = 20 * 4 + 60 * 3 = 80 + 180 = 260 seconds

From second km onwards the bus stops 4 times (beginning, 250m, 500m, and 750m)
Total time taken (in seconds) = 20 * 4 + 60 * 4 = 80 + 240 = 320 seconds
The time taken for the second km is repeated for 3rd till 6th km, hence the time taken for 2nd till 6th km = 320 * 5 = 1600 seconds

Total time taken in journey of 6 km = 260 + 1600 = 1860sec = 31 minutes

Option C

Vetrick · Answer

1. First draw the problem after converting the 6km into 6000 m

2. Convert 45 kmph into m/min -> 45*1000 / 60 = 750 m / min

3. The bus travels 750 m in a min. therefore it travels 250 m in 1/3 min.

4. It travels 24 * 250 m in 1/3*24 = 8 mins.

5. We know that the bus takes 23* 1min breaks .

So, the time the bus takes is 8 + 23 mins = 31 mins.

krishpatel64452 · Answer

Let's solve this question in 2 parts

Part 1 Travel time

The Bus travels at 45km/h that converted into km/m is 0.75

So, applying T = d/s i.e. 6/0.75 that gives us travel time of 8 mins

Part 2 Stoppage time

For 6 km the bus would stop 24 time, but we have to exclude the last stop as the bus would have reached the final stop since it marks the end of the 6 km journey.

so, the bus would stop 23 time each stop being 1min that makes our stoppage time 23 min

now combining part 1 & 2

8mins travelling time + 23 mins Stoppage time = 31mins

MANASH94 · Answer

After doing the calculations wrong twice I have finally done it in a way that I could comprehend better.
 
  A bus travels at a speed of 45 kmph. But it stops every 250 meters at a bus-stop for 1 minute. In how many minutes does the bus cover a distance of 6 kms.
  
If we see that in the entire journey the Bus will make 6 x 4 -1 stops (Every km we can divide it into 4 segments of 250 meters) hence 23 mins of total stoppage time since the final stop the bus will be arriving the destination hence we can remove that count.

Now if the bus wouldn't have stopped then the journey of 6 km would have been completed in 8 mins exactly.
=> 45km/h = 0.75 km/min.

So 6 Kms at a speed of 0.75 km/min = 6/(0.75) = 8 minutes.

Total the bus will take = 23 + 8 minutes. = 31 Minutes.
Answer is C.

Wadree · Answer

45 kph = 45 ×   = 12.5 m / s
After going 250 m ..... Stops for 1 min.......go another 250 m ..... Stop for 1 min..... So AFTER every 250 m ..... Stop for 1 min......look carefully.....AFTER ..... every 250 m.......
So....to go 6000 m .......bus stops for 1 min........ 6000 / 250 = 24 times ..... BUUT..... We don't need da 24th time ....cuz after going 5750 m .....we stop 1 min for da 23rd time...... then we go another 250 and reach 6000 ..... So we dont include da 1 min stop after 6000 m ..... 
So..... total 1 min stop ..... 23 times ..... So.... Total stopping time = 23 min .....
And...... Going 6000 m takes ..... 6000 / 12.5 = 480 s = 8 min .....
So....total time ..... 23 + 8 = 31 min ......

!nah id win!

HarshavardhanR · Answer

- For every 250m (i.e., 1/4 km), the bus takes a time of ((1/4) / 45) * 60 = 1/3 minutes.
- So, for 6 km i.e., 24 x 250m, the bus takes 24 * 1/3 = 8 minutes.
- Now, we have to factor in the stop time. Between the starting point and the finish point, the bus stops 23 times. The 24th stop is the final stop, hence this should not be included. 
- So, time spent in stoppage = 23 x 1 min = 23 minutes.
- Total time taken to cover the 6 km distance = 8 + 23 = 31 minutes.

---
Harsha

A bus travels at a speed of 45 kmph. But it stops every 250 meters at

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A bus travels at a speed of 45 kmph. But it stops every 250 meters at

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