Last visit was: 22 Apr 2026, 08:10 It is currently 22 Apr 2026, 08:10
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
kevincan
User avatar
GMAT Instructor
Joined: 04 Jul 2006
Last visit: 22 Apr 2026
Posts: 1,593
Own Kudos:
Given Kudos: 156
GRE 1: Q170 V170
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
GRE 1: Q170 V170
Posts: 1,593
Kudos: 2,003
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
MA
Joined: 25 Nov 2004
Last visit: 09 Aug 2011
Posts: 695
Own Kudos:
Posts: 695
Kudos: 533
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
v1rok
Joined: 26 Jun 2006
Last visit: 26 Aug 2006
Posts: 69
Own Kudos:
Posts: 69
Kudos: 15
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
sgrover
Joined: 07 Jul 2005
Last visit: 21 Jun 2007
Posts: 246
Own Kudos:
Location: Sunnyvale, CA
Posts: 246
Kudos: 131
Kudos
Add Kudos
Bookmarks
Bookmark this Post
kevincan
Marcia wants to invite at least two of her ten office-mates to her wedding. How many different guest lists could she draw up?

(A) 45 (B) 90 (C) 111 (D) 1113 (E) None of these


pretty big calculation involved:
BUt ans. shd be
10C2 + 10C3 ... + 10C10
Ordering of hte guests doesnt matter..
User avatar
kevincan
User avatar
GMAT Instructor
Joined: 04 Jul 2006
Last visit: 22 Apr 2026
Posts: 1,593
Own Kudos:
Given Kudos: 156
GRE 1: Q170 V170
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
GRE 1: Q170 V170
Posts: 1,593
Kudos: 2,003
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hint: How many guest lists could she draw up if she could invite any number of workmates (i.e. 0,1,2,3,4,5,6,7,8,9 or 10)?
User avatar
sharadGmat
Joined: 20 Feb 2006
Last visit: 01 Mar 2012
Posts: 177
Own Kudos:
Posts: 177
Kudos: 969
Kudos
Add Kudos
Bookmarks
Bookmark this Post
kevincan
Hint: How many guest lists could she draw up if she could invite any number of workmates (i.e. 0,1,2,3,4,5,6,7,8,9 or 10)?


10C0+10C1+10C2 + 10C3 ... + 10C10 isn't it ??
User avatar
kevincan
User avatar
GMAT Instructor
Joined: 04 Jul 2006
Last visit: 22 Apr 2026
Posts: 1,593
Own Kudos:
Given Kudos: 156
GRE 1: Q170 V170
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
GRE 1: Q170 V170
Posts: 1,593
Kudos: 2,003
Kudos
Add Kudos
Bookmarks
Bookmark this Post
For each of the 10 collegues, the girl has two choices, include or exclude?

So there are 2^10 ways of writing the guest list (assuming there can also be fewer than two people invited)
User avatar
sharadGmat
Joined: 20 Feb 2006
Last visit: 01 Mar 2012
Posts: 177
Own Kudos:
Posts: 177
Kudos: 969
Kudos
Add Kudos
Bookmarks
Bookmark this Post
kevincan
For each of the 10 collegues, the girl has two choices, include or exclude?

So there are 2^10 ways of writing the guest list (assuming there can also be fewer than two people invited)


Didn't think like this before.. But doens't 10C0+10C1+10C2 + 10C3 ... + 10C10 yeild the same answer ? I agree that this could be tougher way to calculate..
User avatar
sharadGmat
Joined: 20 Feb 2006
Last visit: 01 Mar 2012
Posts: 177
Own Kudos:
Posts: 177
Kudos: 969
Kudos
Add Kudos
Bookmarks
Bookmark this Post
kevincan
You're right on both counts!


Gr8.. This would be your answer then.

Total guest lists = 2^10 - 1 = 1023 which has atleast 1 person on the list.

So lists wiht atleast 2 persons = 1023-10 = 1013.. E it is..

Thanks Kevin for awesome explanation.. :)



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderator:
Math Expert
109745 posts