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Difficulty:
75%
(hard)
Question Stats:
18%
(00:53)
correct 82%
(02:12)
wrong
based on 11
sessions
History
Date
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A juice is made by mixing x liters of mango pulp with y liters of orange pulp and 14 liters of water where x and y are non-zero integers, mango pulp costs $6 per 10 liters and orange pulp costs $4 per 10 liters, is x >3?
(1) If water is available free of charge, the juice costs $1.6 per 10 liters (2) If mango pulp had cost 20 cents more per liter, then the cost of the mango pulp used in the juice would have been more than $2 greater than the cost of the orange pulp used in the juice
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A juice is made by mixing x liters of mango pulp with y liters of orange pulp and 14 liters of water where x and y are non-zero integers, mango pulp costs $6 per 10 liters and orange pulp costs $4 per 10 liters, is x >3?
(1) If water is available free of charge, the juice costs $1.6 per 10 liters (2) If mango pulp had cost 20 cents more per liter, then the cost of the mango pulp used in the juice would have been more than $2 greater than the cost of the orange pulp used in the juice
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Solution:
• Mango pulp = \(x\) litres
o Cost of mango pulp =\(\frac{ 6}{10} = $0.6\) per litre
• Orange pulp = \(y\) litres
o Cost of orange pulp =\( \frac{4}{10} = $ 0.4\) per litre
• Water = \(14\) litres • \(x\) and \(y\) are non-zero integers
o \(x\) and \(y\) cannot be negative because they are in litres.
We need to find whether \(x > 3\) or not.
Statement 1:
• Cost of water = \($ 0\) • Cost of juice = \($ 1.6\) per \(10\) litre.
o Cost of juice = \(\frac{1.6}{10} = $ 0.16\) per litre
• Now, the cost of juice = \(\frac{(0.6x + 0.4y + 0)}{(x+y+14)} = 0.16\)
o \(0.6x + 0.4y = 0.16x+0.16y+ 2.24\) o \(0.44x + 0.24y = 2.24\) o \(44x + 24y = 224\) o \(11x + 6y = 56\) o The only possibility is when \(x = 4\) and \(y = 2\).
• Therefore, \(x > 3\)
Hence, statement 1 is sufficient, we can eliminate answer options B, C, and E.
Statement 2:
• The cost of mango pulp is increased by \(20\) cent per litre.
o The new cost of mango pulp = \(0.6 + \frac{20}{100} = $ 0.8\) per litre
• Now, according to the situation given
o \(0.8x > 0.4y + 2\) o \(0.4(2x-y) > 2\) o \((2x-y)>5\) o Minimum possible value of \(x\) is \(4\) and \(y\) is \(1\).
• Therefore, \(x > 3.\)
Hence, statement 2 is also sufficient, the correct answer is Option D.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.