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09 Jul 2006, 03:12
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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How many digits are needed to write 20! in decimal notation?
(A) 16 (B) 17 (C) 18 (D) 19 (E) 20
(A) 16 (B) 17 (C) 18 (D) 19 (E) 20
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10 Jul 2006, 16:40
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from 20!,
I am going to estimate and say
~ = about
20*19*18*17*16*15 = ~20^6 = (2^6 * 10^6)
14*13*12*11*10*9*8*7*6*5 = ~10^10
4*3*2*1 = 24
so finally I get: ~10^16 * 2^7 * 12
D, 19
I am going to estimate and say
~ = about
20*19*18*17*16*15 = ~20^6 = (2^6 * 10^6)
14*13*12*11*10*9*8*7*6*5 = ~10^10
4*3*2*1 = 24
so finally I get: ~10^16 * 2^7 * 12
D, 19
10 Jul 2006, 17:27
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Approximating 20! as
20^5 x 15^5 x 10^5 x 5^5 x 1^5
Approximately 20 digits required.
Going with e. 20.
Good to know a way of solving this.
Kevincan, great questions!
Where are you getting these from?
20^5 x 15^5 x 10^5 x 5^5 x 1^5
Approximately 20 digits required.
Going with e. 20.
Good to know a way of solving this.
Kevincan, great questions!
Where are you getting these from?
