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kevincan
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Only seven triangles are possible.

Prob = 7/20 = 0.35
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corrected! Note that the choice of v is independent of the choice of u. That is to say that u could be the same integer as v and/or w!
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kevincan
corrected! Note that the choice of v is independent of the choice of u. That is to say that u could be the same integer as v and/or w!


if only 7 triangles ar epossible (I just trust on that)

than this addition doesn't make difference...

total varians 6P3 = 6!/3!= 120

Possible= 7*3!=42

42/120= 0.35 thus (E) Pobability 0.12-1

GL!
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If selection of any side is independent of previous selection, then we could select 3 sides in 6*6*6=216 ways.

as explained in other posts only 7 possible ways to form triangle

prob=7/216 = .03
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...and for each of these 7, there are 6 ways to write the combination, each of which you have counted in 6^3.

so (6*7)/(6*6*6) or about 7/36.

7/36 > (6/36 = 1/6) and 1/6 is already in [0.12,1), so

E

assuming we're choosing each element with replacement.
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Interesting question...
I misinterpreted the question thinking that we can pick the same digit multiple times.

20 different combinations of 3 digits with 7 options adding to a Scalene triangle. therefore, prob. = 7/20 = .35



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