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kevincan
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Above is a drawing of a wrought iron headboard for a bed. It 15 Aug 2006, 15:42
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Above is a drawing of a wrought iron headboard for a bed. It consists of a straight bar that is 8 feet long, a curved bar in the form of a semi-circle and 30 bars of varying length that are evenly spaced apart. Approximately how many feet of wrought iron are needed to make the headboard?

(A) 90 (B)95 (C)100 (D)105 (E) 110



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Above is a drawing of a wrought iron headboard for a bed. It 16 Aug 2006, 00:01
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this is twisted! :twisted: ... any hints kevincan?
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Above is a drawing of a wrought iron headboard for a bed. It 16 Aug 2006, 01:40
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How can we estimate the average length of the 30 bars?
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Above is a drawing of a wrought iron headboard for a bed. It 16 Aug 2006, 10:24
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kevincan
Above is a drawing of a wrought iron headboard for a bed. It consists of a straight bar that is 8 feet long, a curved bar in the form of a semi-circle and 30 bars of varying length that are evenly spaced apart. Approximately how many feet of wrought iron are needed to make the headboard?

(A) 90 (B)95 (C)100 (D)105 (E) 110
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d= 8
r = 4
half perimeter = 2 (pi) r/2 = (22/7) 4 = 12.57
length of longest string = 4
length of shortest string = 1.44 (detail later, if needed)
avg. of length of 15 (its same for 30) strings = (4 + 1.44)/2 = 2.72

so lenngth of 30 strings = 30 x 2.72 = 81.54

so the total length = d + half perimeter + the length of 30 strings
= 8 + 12.57 + 81.54 = 102.11 :roll: => not in the OAs. seems i missed something.
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Above is a drawing of a wrought iron headboard for a bed. It 16 Aug 2006, 10:43
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The longest bar will be less slightly than 4, so maybe you can round the option to 100.
Not sure thought how much the approximation will impact.
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Above is a drawing of a wrought iron headboard for a bed. It 16 Aug 2006, 17:30
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The longest bars will be less slightly than 4, so maybe you can round the option to 100.
Not sure thought how much the approximation will impact.
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yah, overlooked that one. since there is no sting like r.



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