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How many positive three-digit positive integers are multiples of 6, 9 and 7?
(A) 3 (B) 4 (C) 6 (D) 7 (E) 8
(A) 3 (B) 4 (C) 6 (D) 7 (E) 8
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19 Sep 2006, 14:06
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(D) 7
I am presuming multiples of 6 & 7 & 9, not independently.
LCM (6,7,9) = 126
Three digit +ve integers... {100... 999}
First multiple of 126 after 100 = 126
Last multiple of 126 < 999 = 882
# of multiples = (882-126)/126 +1 (inclusive)
= 7-1 +1 = 7
Answer: D. 7
I am presuming multiples of 6 & 7 & 9, not independently.
LCM (6,7,9) = 126
Three digit +ve integers... {100... 999}
First multiple of 126 after 100 = 126
Last multiple of 126 < 999 = 882
# of multiples = (882-126)/126 +1 (inclusive)
= 7-1 +1 = 7
Answer: D. 7
20 Sep 2006, 05:31
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How many positive three-digit positive integers are multiples of 6, 9 and 7?
(A) 3 (B) 4 (C) 6 (D) 7 (E) 8
the intiger will be in the form of LCM OF (6,9,7)*K WHERE K IS ANY POSITIVE INTIGER
lcm = 7*3^2*2 = 126
now lets name our intiger K
126 < 126K<999
1< K <7.9...K COULD ONLY BE INTIGER , THUS 1=<K=<7
NUMBER OF MULTIPLES IS THUS 7-1+1 = 7
(A) 3 (B) 4 (C) 6 (D) 7 (E) 8
the intiger will be in the form of LCM OF (6,9,7)*K WHERE K IS ANY POSITIVE INTIGER
lcm = 7*3^2*2 = 126
now lets name our intiger K
126 < 126K<999
1< K <7.9...K COULD ONLY BE INTIGER , THUS 1=<K=<7
NUMBER OF MULTIPLES IS THUS 7-1+1 = 7
