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Originally posted by Animesh0001 on 03 Jul 2021, 07:40.
Last edited by Animesh0001 on 03 Jul 2021, 08:50, edited 1 time in total.
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Two trains 150 miles apart are travelling towards each other along the same track. The first train runs at 60 miles/hr and the second train is running at 90 miles/hr. A bird is sitting at front of engine of the first train. It flies from the first train to the second train and turns around immediately flying back to the first train and turns around again. It goes on flying back and forth until they collide. If the bird speed is 120 miles/hr , find the distance travelled by the bird in the direction of first train and in the direction of second train.
ANSWERS are : In the direction of Train 1(FIRST TRAIN) :90 miles, In the direction of Train 2(SECOND TRAIN) :30 miles
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Originally posted by Kinshook on 03 Jul 2021, 08:40.
Last edited by Kinshook on 03 Jul 2021, 08:52, edited 1 time in total.
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Given: Two trains 150 miles apart are travelling towards each other along the same track. The first train runs at 60 miles/hr and the second train is running at 90 miles/hr. A bird is sitting at front of engine of the first train. It flies from the first train to the second train and turns around immediately flying back to the first train and turns around again. It goes on flying back and forth until they collide.
Asked: If the bird speed is 120 miles/hr , find the distance travelled by the bird in the direction of first train and in the direction of second train.
Distance between the 2 trains = 150 miles Relative speed of the 2 trains = 60 + 90 = 150 miles / hr Time taken till they collide = 150/150 = 1 hour
Total distance travelled by the bird during 1 hour = 120 miles /hour * 1 hour = 120 miles
Distance travelled by the bird in the direction of first train = (150 - 60) = 90 miles Distance travelled by the bird in the direction of second train = 120 - 90 = 30 miles
Given: Two trains 150 miles apart are travelling towards each other along the same track. The first train runs at 60 miles/hr and the second train is running at 90 miles/hr. A bird is sitting at front of engine of the first train. It flies from the first train to the second train and turns around immediately flying back to the first train and turns around again. It goes on flying back and forth until they collide.
Asked: If the bird speed is 120 miles/hr , find the distance travelled by the bird in the direction of first train and in the direction of second train.
Distance between the 2 trains = 150 miles Relative speed of the 2 trains = 60 + 90 = 150 miles / hr Time taken till they collide = 150/150 = 1 hour
Total distance travelled by the bird during 1 hour = 120 miles /hour * 1 hour = 120 miles
Distance travelled by the bird in the direction of first train = (150 - 60t) = 90 miles Distance travelled by the bird in the direction of second train = 120 - 90 = 30 miles
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Could you please elaborate more on the logic of the equation 150-60t=90 miles. Thanks.
Given: Two trains 150 miles apart are travelling towards each other along the same track. The first train runs at 60 miles/hr and the second train is running at 90 miles/hr. A bird is sitting at front of engine of the first train. It flies from the first train to the second train and turns around immediately flying back to the first train and turns around again. It goes on flying back and forth until they collide.
Asked: If the bird speed is 120 miles/hr , find the distance travelled by the bird in the direction of first train and in the direction of second train.
Distance between the 2 trains = 150 miles Relative speed of the 2 trains = 60 + 90 = 150 miles / hr Time taken till they collide = 150/150 = 1 hour
Total distance travelled by the bird during 1 hour = 120 miles /hour * 1 hour = 120 miles
Distance travelled by the bird in the direction of first train = (150 - 60t) = 90 miles Distance travelled by the bird in the direction of second train = 120 - 90 = 30 miles
Could you please elaborate more on the logic of the equation 150-60t=90 miles. Thanks.
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The bird could have travelled min (150, 120) = 120 miles if the second train was stationary. Now since second train has moved 60*1 = 60 miles The bird has travelled 150 - 60 = 90 miles in the direction of first train since second train has moved 60*1 = 60 miles
Given: Two trains 150 miles apart are travelling towards each other along the same track. The first train runs at 60 miles/hr and the second train is running at 90 miles/hr. A bird is sitting at front of engine of the first train. It flies from the first train to the second train and turns around immediately flying back to the first train and turns around again. It goes on flying back and forth until they collide.
Asked: If the bird speed is 120 miles/hr , find the distance travelled by the bird in the direction of first train and in the direction of second train.
Distance between the 2 trains = 150 miles Relative speed of the 2 trains = 60 + 90 = 150 miles / hr Time taken till they collide = 150/150 = 1 hour
Total distance travelled by the bird during 1 hour = 120 miles /hour * 1 hour = 120 miles
Distance travelled by the bird in the direction of first train = (150 - 60t) = 90 miles Distance travelled by the bird in the direction of second train = 120 - 90 = 30 miles
Could you please elaborate more on the logic of the equation 150-60t=90 miles. Thanks.
Posted from my mobile device
The bird could have travelled min (150, 120) = 120 miles if the second train was stationary. Now since second train has moved 60*1 = 60 miles The bird has travelled 150 - 60 = 90 miles in the direction of first train since second train has moved 60*1 = 60 miles
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I am little confused about the first part. If we consider second train to be stationary: D=150miles T1=60miles an hr so Train 1 would actually take 150/60=2.5hrs to meet the stationary second train. In that 2.5 hr bird would travel =120×2.5=300 miles. Am I doing something wrong?
Two trains 150 miles apart are travelling towards each other along the same track. The first train runs at 60 miles/hr and the second train is running at 90 miles/hr. A bird is sitting at front of engine of the first train. It flies from the first train to the second train and turns around immediately flying back to the first train and turns around again. It goes on flying back and forth until they collide. If the bird speed is 120 miles/hr , find the distance travelled by the bird in the direction of first train and in the direction of second train.
ANSWERS are : In the direction of Train 1(FIRST TRAIN) :90 miles, In the direction of Train 2(SECOND TRAIN) :30 miles
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Please follow the rules for posting a question.
What is the source? Why would you want the trains collide? They could have easily been on two parallel tracks There are various versions but none asks for distance bee/fly/bird travels in a particular direction.
Even the answers you have given are surely wrong.
If the bird sits on train 1, it will travel towards train 2 first, and so the distance in the direction of second train has to be more. Train 2: 90 and bird 120, so when they would have covered 150 between themselves, the bird would have traveled 120/210 of it or 150*120/210=600/7 or 86 approx. next it will move towards train 1, and then again back in the direction of train 2. so answer is surely more than 86, as it will be 86+….
Where as the answer gives 30 in the direction of second train.
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.