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13 Oct 2006, 03:26
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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The staff of a company is such that there are 7 women for every 11 men. A goverment tax-break is granted to companies in which at least 40% of the employees are women, To qualify for the tax-break, the company has decided to lay off a number of men and replace them with an equal number of women. Unless the company lays off at least 10 men, it will not qualify for the tax-break. How many possibilities are there for the current number of employees in the company?
(A) 1 (B) 2 (C) 3 (D) 4 (E) more than 4
(A) 1 (B) 2 (C) 3 (D) 4 (E) more than 4
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13 Oct 2006, 09:20
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¡Qué escueto! How brief! Care to show us how you arrived at your answer?
14 Oct 2006, 11:21
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(7x +10)/18x > 40%
=> 7x + 10 > 7.2x
=> 0.2x < 10
x = 1,2,3,4 (not zero, since the denominator would become zero)
hence D
=> 7x + 10 > 7.2x
=> 0.2x < 10
x = 1,2,3,4 (not zero, since the denominator would become zero)
hence D
