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keeeeeekse
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I did it this way:

stem can be reduced to:

10 + 10y/ (x + y) = K

Now considering 10y/ (x + y) only ,

let 10y/ (x + y) = C (a constant)

y = x( 10 - C) / C
if C =1 and x = 1, y = 9
if C = 2 and x = 1, y = 4

Substituting each in the reduced equation,

K = 19, 18
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MBAlad
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Quote:
stem can be reduced to:

10 + 10y/ (x + y) = K


How did you reduce it to that?
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dred
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Look at this scenario...

y>x, 3>2

10x + 20y = k(x+y)

10x2 + 20x3 = k (5)

Here k = 80/5 = 16.

y>x , 4>1

Here k = 90/5 = 18.

Am I missing something. Is there a better way to solve this...so substitution might not really work out.
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josh478
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Even more simple:

if x=2 and y=2
1/2*10 + 1/2*20=k

k=15

answer choices would make the difference
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sujayb
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MBAlad
Quote:
stem can be reduced to:

10 + 10y/ (x + y) = K

How did you reduce it to that?


10x/(x+y) + 20y/(x + y) = K

or, 10x/(x + y) + 10y/(x + y) + 10y/(x + y) = K

or, 10(x + y)/(x+y) + 10y/(x+y) = K

or 10 + 10y/(x+y) = K

hth
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josh478
Even more simple:

if x=2 and y=2
1/2*10 + 1/2*20=k

k=15

answer choices would make the difference


y is > x :)



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