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16 Aug 2022, 20:14
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
15% (01:48) correct
85%
(01:40)
wrong
based on 13
sessions
History
Date
Time
Result
Not Attempted Yet
The brokerage to be paid on a share is 0.6x where x is the number of shares bought before it. If the average brokerage per share should not exceed rupees 15, what is the maximum number of shares that can be bought?
A. 24
B. 25
C. 26
D. 50
E. 51
(adapted from gmatfree)
A. 24
B. 25
C. 26
D. 50
E. 51
(adapted from gmatfree)
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01 Sep 2022, 09:15
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pintukr
Buying 1 share brokerage = 0 x 0.6 ( 0 shares brought before this)
Buying 2 shares brokerage = 1 x 0.6 ( 1 share brought before this)
Buying 3 shares brokerage = 2 x 0.6 ( 2 shares brought before this)
....
....
Buying n+1 shares brokerage = n x 0.6 ( n shares brought before this)
Now the average brokerage
(0x0.6 + 1x0.6 + 2x0.6 + --------- + nx0.6) / n+1 <= 15
=> 0.6 (0 + 1 + 2 + ........... + n) <= 15(n+1)
=> 0.6 x n(n+1)/2 <= 15(n+1)
=> 0.6 n <= 30
=> n <= 50
Maximum shares that can be bought at brokerage =15 is n+1 = 50+1 = 51
Option E
Archived Topic
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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