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11 Sep 2022, 11:49
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B
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Difficulty:
55%
(hard)
Question Stats:
71% (03:10) correct
29%
(03:13)
wrong
based on 14
sessions
History
Date
Time
Result
Not Attempted Yet
There are two cities A and B which are 150 km apart. A train T1 from A to B leaves A at 12 noon and travels at 50 km/hr towards B. Another train T2 from A to B leaves A at 11:30 am and travels at 20 km/hr towards B. A third train T3 , travelling at 30 km/hr, leaves B towards A just when T1 crosses T2. When will train T3 meet train T1?
A. 1:30 PM
B. 2:00 PM
C. 2:30 PM
D. 3:00 PM
E. 3:30 PM
(adapted from Varsity Tutors)
A. 1:30 PM
B. 2:00 PM
C. 2:30 PM
D. 3:00 PM
E. 3:30 PM
(adapted from Varsity Tutors)
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20 Sep 2022, 20:35
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let after t hour T1 meets T2 and after x hour of that meeting T1 meets T3
so, 50t = 20( t+.5)
t =1/3
distance traveled by T1 = 50/3
remaining distance =150-(50/3)
so, 50x+30x =150-(50/3)
x=5/3
so total time =1/3+5/3=2 hour
T1 and T3 meets at 2pm
Posted from my mobile device
so, 50t = 20( t+.5)
t =1/3
distance traveled by T1 = 50/3
remaining distance =150-(50/3)
so, 50x+30x =150-(50/3)
x=5/3
so total time =1/3+5/3=2 hour
T1 and T3 meets at 2pm
Posted from my mobile device
20 Sep 2022, 21:16
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Given: There are two cities A and B which are 150 km apart. A train T1 from A to B leaves A at 12 noon and travels at 50 km/hr towards B. Another train T2 from A to B leaves A at 11:30 am and travels at 20 km/hr towards B. A third train T3 , travelling at 30 km/hr, leaves B towards A just when T1 crosses T2.
Asked: When will train T3 meet train T1?
Train T1: -
Distance travelled = 50t
Train T2: -
Distance travelled = .5*20 + 20t = 10 + 20t
Time when train T1 crosses T2: -
50t = 10 + 20t
30t = 10
t = 1/3 hours = 20 minutes
Train T1 crosses train T2 at 12:20 hrs
Train T3: -
Distance travelled = 30(t-1/3) = 30t - 10
When train T1 meets train T3: -
Distance travelled = 50t + 30t - 10 = 150
80t = 160
t = 2 hours
Train T1 meets train T3 at 2 PM
IMO B
Asked: When will train T3 meet train T1?
Train T1: -
Distance travelled = 50t
Train T2: -
Distance travelled = .5*20 + 20t = 10 + 20t
Time when train T1 crosses T2: -
50t = 10 + 20t
30t = 10
t = 1/3 hours = 20 minutes
Train T1 crosses train T2 at 12:20 hrs
Train T3: -
Distance travelled = 30(t-1/3) = 30t - 10
When train T1 meets train T3: -
Distance travelled = 50t + 30t - 10 = 150
80t = 160
t = 2 hours
Train T1 meets train T3 at 2 PM
IMO B
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
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Thank you for understanding, and happy exploring!
