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Bunuel
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Group A and Group B:

A 1, B 7
A = 8C1, B = 8C7 = 2(8)

A 2, B 6
A = 8C2, B = 8C6 = 2(28)

A 3, B 5
A = 8C3, B= 8C5 = 2(56)

A 4, B4
A = 8C4, B= 8C4 = 2(70)

Total number of ways to arrange =

2(8) + 2(28) + 2(56) + 2(70) = 324

Number ways to arrange 8 into two groups of 4:
140

Simplify: 140/324 = 35/81

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­I have a difference in opinion to DivyaBachu, however, it's mathematics and there can be only one unambiguous answer to a properly worded problem. I did it like this:

8 different people in 2 different groups can be formed in \(2^8 \) ways, but this includes zero people in each group so we need to exlude these 2 combinations, so total possible outcomes for us = \(2^8 - 2\)­ = 254

Now, calculating total favorable outcomes is simple. We need 4 people in each group and this can be done in \(^8C_4\) ways­ = \(\frac{8*7*6*5}{4*3*2*1}\) i.e. ­70

Probability = \(\frac{70}{254}\) i.e. \(\frac{35}{127}­\)

Please correct me if I am wrong.­ I did not assume that the groups were identical and I think we should not do that as the question doesn't state it explicitly, right?­
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Hi deemat !
Why in A 4 , B 4 do you multiply by two?
In the other cases I get it, for example in A 1 , B 7, it could be that A is a group of 1 and B of 7 or that A is a group of 7 and B of 1.
But in A 4 , B 4 isn't there only 1 case?
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­To find the probability that eight people are divided into two groups with exactly four members in each, we can use the following steps:

  1. Total ways to divide the group into two subgroups:

    Since the two groups are indistinguishable, each unique grouping of 4 people can only be paired with the remaining 4 people in one way. The combination formula gives the total number of ways to select 4 people out of 8: 8C4

    Since the order of the groups doesn't matter: 8C4/2 = 35

  2. Total ways to divide into any two groups with at least 1 member in each:

    The total number of ways to divide 8 people into two non-empty groups is 2^8−2, which accounts for all possible ways to assign each person to a group minus the two cases where all are in one group (either all 8 in one group and 0 in the other, which are not allowed):

    However, since the groups are indistinguishable, each division is counted twice, so we need to divide by 2:

    2^8−2=254 (subtracting the two cases where one group is empty)Since we count each partition twice (Group A and Group B are indistinguishable):

    254/2=127

  3. Probability calculation:

    The probability P of dividing the 8 people into two groups of exactly 4 members each is the ratio of the number of favourable outcomes to the total number of possible divisions:

    P=Number of favorable outcomes/Total number of possible divisions = 35/127


So, the correct answer is: 35/127 (B)­
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