Last visit was: 22 Apr 2026, 23:53 It is currently 22 Apr 2026, 23:53
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
User avatar
sgoll
User avatar
Joined: 12 Sep 2006
Last visit: 06 Mar 2007
Posts: 52
Own Kudos:
123
Posts: 52
Kudos: 123
PS: ice-cream sign 13 Feb 2007, 08:41
Kudos
Add Kudos
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

History

Date
Time
Result
Not Attempted Yet
Pls explain. I am stuck at the point where i need to find the length of the two sides of the triangle.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
User avatar
sgoll
User avatar
Joined: 12 Sep 2006
Last visit: 06 Mar 2007
Posts: 52
Own Kudos:
123
Posts: 52
Kudos: 123
PS: ice-cream sign 13 Feb 2007, 08:55
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I found the question on another thread. The step to find the base is well explained in the last post on the thread below.

https://www.gmatclub.com/phpbb/viewtopic.php?t=18922

Cheers!
User avatar
Tuneman
User avatar
Joined: 12 Feb 2007
Last visit: 08 Nov 2009
Posts: 103
Own Kudos:
3
Posts: 103
Kudos: 3
PS: ice-cream sign 13 Feb 2007, 12:28
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Sorry I do not understand how to find that base of the triangle. Could someone go through it, I do not see how knowing it iscosoles helps you
User avatar
sgoll
User avatar
Joined: 12 Sep 2006
Last visit: 06 Mar 2007
Posts: 52
Own Kudos:
123
Posts: 52
Kudos: 123
PS: ice-cream sign 13 Feb 2007, 13:48
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Required is the Perimeter of the 2 sides of the triangle+3/4permeter of the circle.

3/4 Perimeter of the circle = 3/4*2*Pie*2 (radius, r=2)
= 3 Pie

Now to find the sides of the triangle, we should know the base.
To find the base, the attached pic may be helpful. As the radii form a right anbgle at the center, the triangle inside the circle is an isocsles triangle with sides = 2 (radius)

By Pythogoreon Theorem Base = 2* sqrt (2)

We have the base and height (5)

Again by Pythogoreon theorem

Side = sqrt (25 + 2) [Notice that we have to consider 1/2 of the base]
=3sqrt (3)

Hence, total req perimeter = 3+2*3sqrt(3)
= 3+6*sqrt(3) [2 represents for two sides]


Hope this helps.
Attachments

ice-cream1.JPG
ice-cream1.JPG [ 6.41 KiB | Viewed 1862 times ]

User avatar
trivikram
User avatar
Joined: 28 Mar 2006
Last visit: 25 May 2018
Posts: 669
Own Kudos:
65
Posts: 669
Kudos: 65
PS: ice-cream sign 13 Feb 2007, 16:31
Kudos
Add Kudos
Bookmarks
Bookmark this Post
sgoll
Required is the Perimeter of the 2 sides of the triangle+3/4permeter of the circle.

3/4 Perimeter of the circle = 3/4*2*Pie*2 (radius, r=2)
= 3 Pie

Now to find the sides of the triangle, we should know the base.
To find the base, the attached pic may be helpful. As the radii form a right anbgle at the center, the triangle inside the circle is an isocsles triangle with sides = 2 (radius)

By Pythogoreon Theorem Base = 2* sqrt (2)

We have the base and height (5)

Again by Pythogoreon theorem

Side = sqrt (25 + 2) [Notice that we have to consider 1/2 of the base]
=3sqrt (3)

Hence, total req perimeter = 3+2*3sqrt(3)
= 3+6*sqrt(3) [2 represents for two sides]


Hope this helps.
Show more


Can you please explain how is the triangle a right angled isoceles triangle? Please see the text in red above
User avatar
devilmirror
User avatar
Joined: 04 Jan 2006
Last visit: 18 Oct 2008
Posts: 101
Own Kudos:
124
Posts: 101
Kudos: 124
PS: ice-cream sign 13 Feb 2007, 18:43
Kudos
Add Kudos
Bookmarks
Bookmark this Post
trivikram
sgoll
Required is the Perimeter of the 2 sides of the triangle+3/4permeter of the circle.

3/4 Perimeter of the circle = 3/4*2*Pie*2 (radius, r=2)
= 3 Pie

Now to find the sides of the triangle, we should know the base.
To find the base, the attached pic may be helpful. As the radii form a right anbgle at the center, the triangle inside the circle is an isocsles triangle with sides = 2 (radius)

By Pythogoreon Theorem Base = 2* sqrt (2)

We have the base and height (5)

Again by Pythogoreon theorem

Side = sqrt (25 + 2) [Notice that we have to consider 1/2 of the base]
=3sqrt (3)

Hence, total req perimeter = 3+2*3sqrt(3)
= 3+6*sqrt(3) [2 represents for two sides]


Hope this helps.

Can you please explain how is the triangle a right angled isoceles triangle? Please see the text in red above
Show more


You know that:
Circumference = 2 x Pi x r

If r is constant, we can conclude that circumference (or length of sector) is proportional to its angle (= 360 degrees).

Therefore; (Length of sector) α (angle of the sector)

S1/S2 = Angle1/Angle2

We can use this knowledge to find any angle if we know the length sector of the circle and we know the length of the circumference.

From the picture, the circumference = 2 x Pi x 2 = 4Pi
and the top sector on the ice cream has length = (3/4) x 4 Pi = 3Pi

The length of the sector under the triangle that you questioned = 4Pi - 3Pi = Pi

Put all info into the equation that I set above.

S1 = Pi
S2 = Circumference of the circle = 4Pi
Angle1 = what we want to know
Angle2 = 360 (Angle of the circumference)

Pi/4Pi = Angle1/360

Angle1 = 360 x 1/4 = 90 degrees

-------------------------------------------------

Or you can use this equation to find the angle of any sector

Length of sector = Angle of the sector x radius

S = @r
Pi = @ x 2
@ = Pi/2

We know that Pi/2 is 90 degrees.
User avatar
amorpheus
User avatar
Joined: 10 Dec 2005
Last visit: 26 Feb 2007
Posts: 48
Own Kudos:
15
Posts: 48
Kudos: 15
PS: ice-cream sign 13 Feb 2007, 19:22
Kudos
Add Kudos
Bookmarks
Bookmark this Post
trivikram
sgoll
Required is the Perimeter of the 2 sides of the triangle+3/4permeter of the circle.

3/4 Perimeter of the circle = 3/4*2*Pie*2 (radius, r=2)
= 3 Pie

Now to find the sides of the triangle, we should know the base.
To find the base, the attached pic may be helpful. As the radii form a right anbgle at the center, the triangle inside the circle is an isocsles triangle with sides = 2 (radius)

By Pythogoreon Theorem Base = 2* sqrt (2)

We have the base and height (5)

Again by Pythogoreon theorem

Side = sqrt (25 + 2) [Notice that we have to consider 1/2 of the base]
=3sqrt (3)

Hence, total req perimeter = 3+2*3sqrt(3)
= 3+6*sqrt(3) [2 represents for two sides]


Hope this helps.

Can you please explain how is the triangle a right angled isoceles triangle? Please see the text in red above
Show more


It is right angle triangle because the sector is 1/4 of the whole circle therefore 360/4 = 90
User avatar
prude_sb
User avatar
Joined: 12 Mar 2006
Last visit: 13 Jul 2020
Posts: 189
Own Kudos:
264
Given Kudos: 3
Concentration: Management, Strategy & Finance
Schools:Kellogg School of Management
Posts: 189
Kudos: 264
PS: ice-cream sign 13 Feb 2007, 22:36
Kudos
Add Kudos
Bookmarks
Bookmark this Post
perimeter of the circular portion is 3*2*pi*2/4

The base of the triangle is sqrt(2)*2

The other sides of the triangle are sqrt(25+2) = 3*sqrt(3)

so perimeter is 6*sqrt(3) + 3*pi

B



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderator:
Bunuel
Math Expert
109763 posts