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Of the vehicles (cars and trucks) for sale at a certain dealership, 48 percent are cars that have 4 doors. If 80 percent of the cars for sale at the dealership have 4 doors, what percent of the vehicles are cars that do not have 4 doors?

A. 12%
B. 20%
C. 24%
D. 32%
E. 40%

Attachment:
The attachment 2024-01-29_12-32-49.png is no longer available

We know that:

  • 48% of the total vehicles are cars AND have 4 doors.
  • 80% of the cars have 4 doors.

This means that 0.8 * {cars} = 0.48 * {total}.

On the other hand, since 80% of the cars have 4 doors, it means that 20% of cars do not have 4 doors. We are asked to find what 0.2*{cars} is as a percent of the total. Since 0.8 * {cars} = 0.48 * {total}, then 0.2 * {cars} will be a quarter of that, so 0.12 * {total}.

Answer: A.

P.S. Check the image below for a better understanding:



Attachment:
Cars.png
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DALC1

Given: Of the vehicles (cars and trucks) for sale at a certain dealership, 48 percent are cars that have 4 doors.
Asked: If 80 percent of the cars for sale at the dealership have 4 doors, what percent of the vehicles are cars that do not have 4 doors?


CarsTrucksTotal
4 doors48%
~4 doors
Total48%/80% = 60%100%


CarsTrucksTotal
4 doors48%
~4 doors60%-48%=12%
Total48%/80% = 60%100%

IMO A
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Let the total vehicles be x
Let the total cars be y
Then — 48/100x = 80/100y
Now, through this we get 60/100 = y/x

That is 60% are total cars, amongst which 48% are 4 doors, so the cars that donot have 4 doors = 60-48 = 12%.

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Let the total number of vehicles at the dealership be V
Let the total number of cars at the dealership be C

We know that 48% of the total vehicles are cars with 4 doors:
Cars with 4 doors = 0.48⋅V

We also know that 80% of all cars have 4 doors:
Cars with 4 doors=0.8⋅C
These two quantities must be the same because they both represent the number of cars with 4 doors:
0.8⋅C=0.48⋅V

C= 0.48⋅V / 0.8 =0.6 V

This means that 60% of the total vehicles are cars.

Calculate the percentage of cars that do NOT have 4 doors:

Out of all the cars, 80% have 4 doors. Therefore, the remaining 20% of the cars do NOT have 4 doors.

The total number of cars is 0.6 ⋅ V and 20% of these do not have 4 doors:

Cars without 4 doors = 0.2⋅ (0.6⋅V)=0.12⋅V
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all of this answers are too complicated for me, so I found easy one, like most simple. So 48% of 4d - is 80% of all cars, then 20% is no 4d cars. Proportion 48/x = 80/20; 48*20/80 = 12. I spent about 10 minutes to understand it, idk why my mind couldn't find so simple answer :/
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Let's assume we're working with 100 cars

48 percent (or 48 of 100) are cars that have 4 doors

80 percent of the cars at dealership have 4 doors: 4/5x = 48 so x = 60

60 - 48 = 12

12/100 = 12%


CarsTrucksTotal
Four Doors48
Two Doors12
Total60100
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DALC1
Of the vehicles (cars and trucks) for sale at a certain dealership, 48 percent are cars that have 4 doors. If 80 percent of the cars for sale at the dealership have 4 doors,cwhat percent of the vehicles are cars that do not have 4 doors?

(A) 12%
(B) 20%
(C) 24%
(D) 32%
(E) 40%

Of the vehicles (cars and trucks) for sale at a certain dealership, 48 percent are cars that have 4 doors.

So if there are 100 vehicles for sale, 48 are 4-door cars.

If 80 percent of the cars for sale at the dealership have 4 doors, what percent of the vehicles are cars that do not have 4 doors?

Of the cars, 80% has 4-doors and 20% do not have 4-doors. So the ratio of cars with 4-doors and no 4-doors is 4 : 1.
Above, since 48 cars have 4-doors, so 12 cars do not have 4-doors.

what percent of the vehicles are cars that do not have 4 doors?

Of 100 vehicles, 12 are cars that do not have 4-doors.

Hence answer (A)
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