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A container contains a mixture of milk and water in the ratio of 4:1. 20 liters of the mixture is removed and replaced with water. this process is repeated one more time. If the final mixture has milk and water in the ratio of 16:9, what was the original quantity of the mixture?
(I dont have the official answer. So can anyone help?)
(I dont have the official answer. So can anyone help?)
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11 Dec 2024, 22:50
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Post the question completely in proper format so that it will be helpful.
In general, these kinds of questions can be dealt with by substituting the options.
For suppose the original mix is of 100l
So M : W = 80 l & 20 L initially.
So if we remove 20 L out of it, The distribution will also be in the same ratio : 4:1 => 16L (M) & 4 L(W).
So resulting solution would be 64L(M) & 16L(W) but it is added with 20L(W). Hence, the final solution would be
64L(M) & 36L(W).
16:9.
So 100L is the original mixture quantity.
Shayan08
Hey Shayan,
Post the question completely in proper format so that it will be helpful.
In general, these kinds of questions can be dealt with by substituting the options.
For suppose the original mix is of 100l
So M : W = 80 l & 20 L initially.
So if we remove 20 L out of it, The distribution will also be in the same ratio : 4:1 => 16L (M) & 4 L(W).
So resulting solution would be 64L(M) & 16L(W) but it is added with 20L(W). Hence, the final solution would be
64L(M) & 36L(W).
16:9.
So 100L is the original mixture quantity.
13 Dec 2024, 04:24
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