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505-555 (Easy)|   Roots|            
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jlgdr
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Bunuel
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jlgdr
4th root of 496 is between

(A) 3 and 4
(B) 4 and 5
(C) 5 and 6
(D) 6 and 7
(E) 7 and 8

\(\sqrt{496} = 22.xx\)

\(\sqrt{22.xx} = 4.xx\)

Thus, the 4th root of 496 is between 4 and 5

Answer will be (B) between 4 and 5
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16 square is 256 and 25 sqaure is 625 , so 496 must lie between 4 and 5 since it is a 4th square root.
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jlgdr
\(\sqrt[4]{496}\) is between

(A) 3 and 4
(B) 4 and 5
(C) 5 and 6
(D) 6 and 7
(E) 7 and 8
­Alternate approach using options , 

(A) 3^4 to 4^4 = 81 to 256 not possible as the no is 496 which is outside range
(B) 4^4 to 5^4 = 256 to 625 Possible.
(C) 5^4 and 6^4 = 625 to 1296 not possible as the no is 496 which is outside range
(D) 6^4 and 7^4 = 1296 to .......... not possible as the no is 496 which is outside range
(E) 7^4 and 7^4 = 2401 to .......... not possible as the no is 496 which is outside range

Answer must be (B)
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\(\sqrt[4]{496}\) is between

(A) 3 and 4
(B) 4 and 5
(C) 5 and 6
(D) 6 and 7
(E) 7 and 8
How do we know that we are looking for the roots here?
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quamminus

How do we know that we are looking for the roots here?
\(\sqrt[4]{496}\) means 4th root of 496.
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