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22 Jun 2007, 01:05
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in a triangle abc , AD frm A to meet BC at D. if BD = 8 cm , DC 2 cm ad AD =4 cm then
1) ABC is an isosceles trianle
2)ABC is an equilateral triangle
3)AC = 2AB
4)ABC right angle triangle
1) ABC is an isosceles trianle
2)ABC is an equilateral triangle
3)AC = 2AB
4)ABC right angle triangle
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22 Jun 2007, 13:18
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the answer is (3)
AC = 2AB
since 4^2+8^2 = AC^2
AC = sqrt(80)
and since 4^2+2^2 = AB^2
AB = sqrt(20)
sqrt(80) = 2*sqrt(20)
sqrt(80) = sqrt(4*20)
AC = 2AB
since 4^2+8^2 = AC^2
AC = sqrt(80)
and since 4^2+2^2 = AB^2
AB = sqrt(20)
sqrt(80) = 2*sqrt(20)
sqrt(80) = sqrt(4*20)
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