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Vlad77
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trancing
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Vlad77
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4 babies where each one of them is either a boy or girl

2 choices for baby 1 * 2 choices for baby 2 * 2 choices for baby 3 * 2 choices for baby 4 = 2 ^4 = 16 total outcomes.

Btw, what answer does the OA give?
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Amit05
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trancing
I believe it goes like this:

total number of outcomes = 2*2*2*2 = 16
total number of outcomes with 2 Boys = 4 choose 2 = 4! / (2!*2!) = 6

answer is 6/16=3/8 (choice D)

Hope this helps!


Good explanation..

Another way I will at it is :

Total outcome is 16.

2 boys off 4 kids, I have following possibilities:

BBGG
BGBG
BGGB
GBGB
GGBB
GBBG

So, 6 possibilities out 16.
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Vlad77
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Thanks :)
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beckee529
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Vlad77
What is the probability of bearing two boys from four born babies?
(A) 1/5
(B) 1/8
(C) 1/2
(D) 3/8
(E) 6/11


got (D) 3/8

2 boys: 4C2 = 4*3 / 2*1 = 6
total: 2^4 = 2*2*2*2 = 16

F/T = 6/16 = 3/8



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