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07 Sep 2007, 07:37
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A housing subdivision contains only two types of homes: ranch-style homes andtownhomes. There are twice as many townhomes as ranch-style homes. There are 3 timesas many townhomes with pools than without pools. What is the probability that a homeselected at random from the subdivision will be a townhome with a pool?
(A) 1/6 (B) 1/5 (C) 1/4 (D) 1/3 (E) 1/2
(A) 1/6 (B) 1/5 (C) 1/4 (D) 1/3 (E) 1/2
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07 Sep 2007, 08:03
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johnycute
I got E,
R is # of ranchhomes
T is # of townhomes
"There are twice as many townhomes as ranch-style homes." translates T=2R. Then total number of houses is 3R
"There are 3 timesas many townhomes with pools than without pools. " translates the ratio of "with pools to without pools" is 3:1. Or 75% {3/4} of T with pools and 1/4 {25%} of T without pools. Then # of houses with pools is 0,75*T or 0,75*2R.
"What is the probability that a homeselected at random from the subdivision will be a townhome with a pool?" translates
# of houses with pools/ total # of houses=?
0,75*2R/3R = 1/2
Please, let know if I missed something.
07 Sep 2007, 08:18
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johnycute
E.
R = x
T = 2x
total = 3x
T (No Pool) = 2x/4
T (Pool) = 2x - 2x/4 = 6x/4
P9Pool) = (6x/4)/3x = 1/2
