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16 Nov 2007, 06:26
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 187, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?
22
33
55
77
88
Solution :
F = Fuji
G = Gala
x = Total no. of trees
x/10 - pollinate
F + x/10 = 187
F = 3x/4 - Pure Figi
3x/4 + x/10 = 187
30x + 4x/40 = 187 * 40
x = 187 * 40 /17 = 220
3/4 * 220 = 54 * 3 = 165 - 187 = 22. --- I'm getting A
Any more takers ??
22
33
55
77
88
Solution :
F = Fuji
G = Gala
x = Total no. of trees
x/10 - pollinate
F + x/10 = 187
F = 3x/4 - Pure Figi
3x/4 + x/10 = 187
30x + 4x/40 = 187 * 40
x = 187 * 40 /17 = 220
3/4 * 220 = 54 * 3 = 165 - 187 = 22. --- I'm getting A
Any more takers ??
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16 Nov 2007, 07:09
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alimad
If the number of pure fuji + number of cross pollinated trees = 187 and the total number of trees = 220. Then isn't the number of pure gala trees = total number of trees - total number of non-gala trees = 220 - 187 = 33 ? Or am i missing something here?
16 Nov 2007, 07:17
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alimad
Ans B.
3x/4 + x/10 = 187
x=220
Pure Gala = 220 - 187 = 33
However if I do
Gala = Total - Pure Fuji - Cross poolinated
= Total - 3/4(Total) - 1/10(Total) = 35
So I am not 100% sure of my answer.
