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17 Dec 2007, 14:47
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Each of a group of children has 3 blue markers and 1 red marker or 2 red markers and 1 blue marker. If the average number of red markers that each child has is 1.6, what is the average number of blue markers that each child has?
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17 Dec 2007, 14:58
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1.8
(1*n+2*m)/(n+m)=1.6
(1+2*m/n)/(1+m/n)=1.6
1+2*m/n=1.6+1.6*m/n
m/n=3/2
blue_av=(3+1*3/2)/(1+3/2)=9/5=1.8
(1*n+2*m)/(n+m)=1.6
(1+2*m/n)/(1+m/n)=1.6
1+2*m/n=1.6+1.6*m/n
m/n=3/2
blue_av=(3+1*3/2)/(1+3/2)=9/5=1.8
17 Dec 2007, 15:41
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walker
Amezing!!!
