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03 Jan 2008, 09:10
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A bag contains 10 balls, each of which is labeled with a distinct
prime number. If 2 balls are to be removed from the bag and
the numbers on the balls are multiplied together, how many
different products are possible?
(A) 10
(B) 45
(C) 50
(D) 90
(E) It cannot be determined from the infomation given.
prime number. If 2 balls are to be removed from the bag and
the numbers on the balls are multiplied together, how many
different products are possible?
(A) 10
(B) 45
(C) 50
(D) 90
(E) It cannot be determined from the infomation given.
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03 Jan 2008, 10:24
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Yup, same thing as thinking "I have 10 choices for my first pick and 9 for my second"
10*9 = 90
but the order doesn't matter since they're just being multiplied by one another. So divide by 2 to get rid of any duplicates (e.g. (3,5) and (5,3))
90/2 = 45
and there's your answer.
The original combination approach is the more correct way to go about it, but using permutations and modifying it works just as well.
10*9 = 90
but the order doesn't matter since they're just being multiplied by one another. So divide by 2 to get rid of any duplicates (e.g. (3,5) and (5,3))
90/2 = 45
and there's your answer.
The original combination approach is the more correct way to go about it, but using permutations and modifying it works just as well.
