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17 Jan 2008, 07:00
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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If an + 1 = 4(an + 1) and a4 = 532, what is the value of a1?
A. 7
B. 8
C. 15
D. 16
E. 32
[spoiler]OA is A[/[spoiler]
A. 7
B. 8
C. 15
D. 16
E. 32
[spoiler]OA is A[/[spoiler]
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17 Jan 2008, 08:25
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A
\(a_{n+1}=4*(a_n+1)\)
\(a_{4}=4*(a_3+1)=4*a_3+4=16*a_2+16+4=64*a_1+64+16+4\)
\(a_1=\frac{532-64-16-4}{64}=\frac{512}{64}-1=7\)
\(a_{n+1}=4*(a_n+1)\)
\(a_{4}=4*(a_3+1)=4*a_3+4=16*a_2+16+4=64*a_1+64+16+4\)
\(a_1=\frac{532-64-16-4}{64}=\frac{512}{64}-1=7\)
17 Jan 2008, 14:21
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AVakil
I'm guessing that An+1 is really A(n+1) and 4(An+1) is 4((An)+1) Anyway
A(3+1) = 4(A3+1) 532 = 4A3+4 528=4A3 --> A3 = 132
A(2+1) = 4(A2+1) --> 132= 4A2+4 --> 128/4=A2 A2=32
A(1+1)= 4(A1+1) --> 28=4A1
7=A1
A
