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az780
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walker
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GMAT 1: 750 Q50 V40
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Schools: Chicago (Booth) - Class of 2011
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This is my logic:

1. we have two different integers.
2. the largest GCD(x,y) of two integers when GCD(x,y)=x
3. if we choose one integer (x), the most closest different integer to give GCD=x is y=2x
4. apply for our problem: the largest integer in the set is 143 but 143 is odd. Therefore, we choose next one - 142 and 142/2=71.
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Thanks for clear explanation!
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rkassal
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az780
What is the greatest common divisor of two different positive integers which are less 144?

Please advise the best approach to this problem.

The answer is 71.
71 is a divisor for 71 and for 142.
rkassal



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