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markup (M) = selling price (S) - cost (C)
-->M=S - C-->S= M + C= 1.2C
M/S = 0.2C/1.2C = 1/6 (half of 1/3)= 0.167 (half of 1/3)--> E
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Bunuel
The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price?
(markup = selling price - cost)

(A) 8%
(B) 10%
(C) 12 1/2%
(D) 15%
(E) 16 2/3%

C = 100
M = 20
S = 120

So, M/S*100 = 20/120*100 = 16 2/3% , Answer must be (E)
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Let the cost price of the television be "\(x\)"

Since markup on the television set is 20% of the cost, Markup = 20 % of \(x = 0.2x\)

Markup = Selling Price - Cost Price

\(0.2x\) = Selling Price - \(x\)

Selling Price = \(1.2x\)

If markup is \(y\)% of the Selling Price, then:

\(y\) = Markup/Selling Price * 100 = \(\frac{0.2x}{1.2x}\) * 100 = \(\frac{1}{6}\) * 100 = 16 \(\frac{2}{3}\) %

The correct answer is E
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Bunuel
The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price?
(markup = selling price - cost)

(A) 8%
(B) 10%
(C) 12 1/2%
(D) 15%
(E) 16 2/3%

The markup is 0.2c, and thus the selling price = c + 0.2c = 1.2c. Therefore, the markup is:

0.2c/(1.2c) = 0.2/1.2 = 2/12 = 1/6 = 16 ⅔%

Answer: E
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Bunuel
The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price? (markup = selling price - cost)


(A) 8%

(B) 10%

(C) \(12 \frac{1}{2}\)%

(D) 15%

(E) \(16 \frac{2}{3}\)%


PS21236

\(CP = 100\) , \(Markup = 20\) & \(SP = 120\)

Markup is what percent of the selling price -

\(\frac{20}{120}*100\) = \(16 \frac{2}{3}\)% , Answer must be (E)
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Bunuel
The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price? (markup = selling price - cost)


(A) 8%

(B) 10%

(C) \(12 \frac{1}{2}\)%

(D) 15%

(E) \(16 \frac{2}{3}\)%


PS21236

CP= 100

SP=120 (Markup + CP)

Markup is what % of SP? 20 is what percent of 120? 1/6 = 16.67%

Answer E
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Bunuel
The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price? (markup = selling price - cost)


(A) 8%

(B) 10%

(C) \(12 \frac{1}{2}\)%

(D) 15%

(E) \(16 \frac{2}{3}\)%


PS21236

cost = \(100\)
markup = \(20\)
selling price = \(120\)

\(\frac{20}{120} = \frac{1}{6} = 16.66\)%

Answer is E.
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Solution



Given
In this question, we are given that
    • The markup on a television set is 20 percent of the cost
    • Markup = selling price – cost

To find
We need to determine
    • The markup is what percent of the selling price

Approach and Working out
Assuming that the television set is sold at the markup price only, if
    • Cost price = 100
    • Then, markup value = profit = 20% of cost price = 20% of 100 = 20
    • Hence, the selling price = 100 + 20 = 120
Therefore, markup as a percentage of the selling price = (20/120) * 100 = 16.67%

Thus, option E is the correct answer.

Correct Answer: Option E
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Mark Cost = Selling price - Cost
Cost = 100/20 Mark Cost

MC = SP - 5 MC
MC/CP = 1/6

E
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