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# The markup on a television set is 20 percent of the cost. The markup

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The markup on a television set is 20 percent of the cost. The markup  [#permalink]

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04 Jun 2019, 00:11
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15% (low)

Question Stats:

82% (01:36) correct 18% (01:47) wrong based on 77 sessions

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The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price? (markup = selling price - cost)

(A) 8%

(B) 10%

(C) $$12 \frac{1}{2}$$%

(D) 15%

(E) $$16 \frac{2}{3}$$%

PS21236

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Re: The markup on a television set is 20 percent of the cost. The markup  [#permalink]

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04 Jun 2019, 00:17
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Cost 100, Profit 20 therefore Selling price 120. Profit on Selling price is 20/120*100 = 16 2/3% Option E
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Re: The markup on a television set is 20 percent of the cost. The markup  [#permalink]

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04 Jun 2019, 03:26
Bunuel wrote:
The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price?
(markup = selling price - cost)

(A) 8%
(B) 10%
(C) 12 1/2%
(D) 15%
(E) 16 2/3%

cost = c
mark up = .2c
so sp= 1.2c
.2c/1,2c = 16 .6%
IMO E
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Re: The markup on a television set is 20 percent of the cost. The markup  [#permalink]

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05 Jun 2019, 01:33
markup (M) = selling price (S) - cost (C)
-->M=S - C-->S= M + C= 1.2C
M/S = 0.2C/1.2C = 1/6 (half of 1/3)= 0.167 (half of 1/3)--> E
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Re: The markup on a television set is 20 percent of the cost. The markup  [#permalink]

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05 Jun 2019, 11:28
Bunuel wrote:
The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price?
(markup = selling price - cost)

(A) 8%
(B) 10%
(C) 12 1/2%
(D) 15%
(E) 16 2/3%

C = 100
M = 20
S = 120

So, M/S*100 = 20/120*100 = 16 2/3% , Answer must be (E)
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Re: The markup on a television set is 20 percent of the cost. The markup  [#permalink]

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07 Jun 2019, 19:25
Let the cost price of the television be "$$x$$"

Since markup on the television set is 20% of the cost, Markup = 20 % of $$x = 0.2x$$

Markup = Selling Price - Cost Price

$$0.2x$$ = Selling Price - $$x$$

Selling Price = $$1.2x$$

If markup is $$y$$% of the Selling Price, then:

$$y$$ = Markup/Selling Price * 100 = $$\frac{0.2x}{1.2x}$$ * 100 = $$\frac{1}{6}$$ * 100 = 16 $$\frac{2}{3}$$ %

The correct answer is E
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Re: The markup on a television set is 20 percent of the cost. The markup  [#permalink]

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09 Jun 2019, 18:05
Bunuel wrote:
The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price?
(markup = selling price - cost)

(A) 8%
(B) 10%
(C) 12 1/2%
(D) 15%
(E) 16 2/3%

The markup is 0.2c, and thus the selling price = c + 0.2c = 1.2c. Therefore, the markup is:

0.2c/(1.2c) = 0.2/1.2 = 2/12 = 1/6 = 16 ⅔%

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The markup on a television set is 20 percent of the cost. The markup  [#permalink]

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22 May 2020, 08:23
Bunuel wrote:
The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price? (markup = selling price - cost)

(A) 8%

(B) 10%

(C) $$12 \frac{1}{2}$$%

(D) 15%

(E) $$16 \frac{2}{3}$$%

PS21236

$$CP = 100$$ , $$Markup = 20$$ & $$SP = 120$$

Markup is what percent of the selling price -

$$\frac{20}{120}*100$$ = $$16 \frac{2}{3}$$% , Answer must be (E)
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Abhishek....

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Re: The markup on a television set is 20 percent of the cost. The markup  [#permalink]

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01 Jun 2020, 20:42
Bunuel wrote:
The markup on a television set is 20 percent of the cost. The markup is what percent of the selling price? (markup = selling price - cost)

(A) 8%

(B) 10%

(C) $$12 \frac{1}{2}$$%

(D) 15%

(E) $$16 \frac{2}{3}$$%

PS21236

CP= 100

SP=120 (Markup + CP)

Markup is what % of SP? 20 is what percent of 120? 1/6 = 16.67%

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Re: The markup on a television set is 20 percent of the cost. The markup   [#permalink] 01 Jun 2020, 20:42

# The markup on a television set is 20 percent of the cost. The markup

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