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29 Oct 2008, 00:43
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29 Oct 2008, 00:55
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Any -ve number under a square root is imaginary - crude definition.
Here sqrt(5) is ~2.2 > 2. Hence Sqrt (2-2.2) is -ve and hence an imaginary number.
Hence (E)
Here sqrt(5) is ~2.2 > 2. Hence Sqrt (2-2.2) is -ve and hence an imaginary number.
Hence (E)
