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26 Sep 2009, 03:23
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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Q.
If V is the volume of a cuboid of dimension x, y, z and A is its surface, then A/V will be equal to
1. x^2*y^2*z^2
2. ½( 1/xy + 1/ xz + 1/ yz)
3. ½ ( 1/x +1/y+1/z)
OA- 3
If V is the volume of a cuboid of dimension x, y, z and A is its surface, then A/V will be equal to
1. x^2*y^2*z^2
2. ½( 1/xy + 1/ xz + 1/ yz)
3. ½ ( 1/x +1/y+1/z)
OA- 3
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26 Sep 2009, 06:34
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Volume of it is equal to V= x*y*z
Area of it is equal to the sum of 6 regions on its surface. There are 2 surfaces with dimensions x and y, two with x and z and two with y and z.
So the area = A= 2*x*y+2*x*z+2*y*z
A/V= 2(xy+xz+yz)/xyz= 2(1/x+1/y+1/z).
It is like option c but not the same. Please control OA
Area of it is equal to the sum of 6 regions on its surface. There are 2 surfaces with dimensions x and y, two with x and z and two with y and z.
So the area = A= 2*x*y+2*x*z+2*y*z
A/V= 2(xy+xz+yz)/xyz= 2(1/x+1/y+1/z).
It is like option c but not the same. Please control OA
26 Sep 2009, 07:44
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virtualanimosity
V = xyz
A = 2 (xy + yz + zx)
A/V= 2(xy+yz+zx) / xyz = 2(1/x + 1/y + 1/z)
If question were what is V/A, then
V/A = xyz / [2(xy+yz+zx)] = 1 / [2 (1/x + 1/y + 1/z)]
In the given answer choices, if u put a extra bracket in the answer choice 3, then that will match with V/A.
