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Area of triangle = (sqrt3/4) s^2 = x meters^2

Perimeter of triangle = 3s = x meters

Equate both of them:
(sqrt3/4) s^2 = 3s
After Solving we get, s= 4(sqrt3)

We need length of one side: s/3 = 4(sqrt3)/3 = 4/sqrt3

Ans: E


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- Prince
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Thank you all. Its very clear now.



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