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25 Apr 2010, 09:02
Kudos
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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Hi all.
A man travels 75% of the way from point A to point B traveling at a speed of 50mph. How fast must he travel the rest of the trip in order to maintain an overall average speed of 40 mph?
Correct Answer: 25
Any suggestions?
A man travels 75% of the way from point A to point B traveling at a speed of 50mph. How fast must he travel the rest of the trip in order to maintain an overall average speed of 40 mph?
Correct Answer: 25
Any suggestions?
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25 Apr 2010, 09:06
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opps ... it seems you don't want to use the spoiler at all.. 
please don't display the answer with the post . take the interest away to solve the problem.
please don't display the answer with the post . take the interest away to solve the problem. 
25 Apr 2010, 09:07
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gmatt14
Assume distance between A and B is 200 miles(i assumed this because its the LCM of 40 and 50).
So if average speed needs to be 40 then time = 200/40 = 5 hrs
75% was traveled at 50 miles/hr, so time taken was = 75%*200/50 = 150/50 = 3 hrs.
So you have 5-3 = hrs to travel the remaining distance(200-150 = 50 miles)
Time taken = distance remaining/time remaining = 50/2 = 25 mi/hr
Cheers
