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26 Apr 2010, 20:04
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The perimeter of a certain isoceles right triangle is 16 + 16\sqrt{2}. what is the hypotenuse of the triangle?
A. 8
B. 16
C. 4\sqrt{2}
D. 8\sqrt{2}
E. 16\sqrt{2}
Source: GMAT Prep
A. 8
B. 16
C. 4\sqrt{2}
D. 8\sqrt{2}
E. 16\sqrt{2}
Source: GMAT Prep
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26 Apr 2010, 22:55
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let one side be x
hypotenuse is x\sqrt{2}
perimeter = 2x + x\sqrt{2} = 16+16\sqrt{2}
solving x = 8\sqrt{2}
hence hypotenuse is 16
hence B.
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