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10 Jun 2019, 01:51
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
75% (02:51) correct
25%
(02:55)
wrong
based on 210
sessions
History
Date
Time
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Not Attempted Yet
A certain industrial machine requires 15 quarts (480 ounces) of oil every day, and it is given a mixture of oil A and oil B. Oil A consists of 5% special additives while oil B consists of 8% special additives. If the machine needs exactly 30 ounces of the special additives to ensure smooth operation, then how much of oil A, in ounces, should be in the mixture?
A. 260
B. 280
C. 290
D. 300
E. 320
A. 260
B. 280
C. 290
D. 300
E. 320
10 Jun 2019, 02:05
Kudos
Bookmarks
So 5%of x and 8% (480-x)= 30
-.03x = 8.4; so x= 280 ounces IMO B
Posted from my mobile device
-.03x = 8.4; so x= 280 ounces IMO B
Posted from my mobile device
10 Jun 2019, 02:54
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Bunuel
Let the required Qty of oil A = x
--> Qty of oil B = 480 - x
Given, 5% of oil A + 8% of oil B = 30
--> 0.05x + 0.08*(480 - x) = 30
--> 0.05x + 38.4 - 0.08x = 30
--> 0.03x = 8.4
--> x = 840/3 = 280
IMO Option B.
Pls Hit kudos if you like the solution
