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26 Jul 2010, 19:14
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Can I get some help here.
A store sells 2 kinds of jelly beans mixes (A and B)both made up of red and yellow beans. if b contains 20% more red beans than A but 10% fewer yellow beans. and Jar A contains twice as many red beans as yellow by what percent is the number of beans in Jar B larger than the number in Jar A
A store sells 2 kinds of jelly beans mixes (A and B)both made up of red and yellow beans. if b contains 20% more red beans than A but 10% fewer yellow beans. and Jar A contains twice as many red beans as yellow by what percent is the number of beans in Jar B larger than the number in Jar A
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26 Jul 2010, 19:50
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Is the answer 10%?
B contains 20% more red beans than A. So lets say A has R red beans then B has 1.2R red beans. Also, A contains 10% more yellow beans than B. So, if B contains Y yellow beans then A contains 1.1Y yellow beans.
Jar A contains twice as many red beans as yellow.
Let say, A has x yellow beans that means there are 2x red beans. So A has 3x beans in total.
So, B has 2.4x read beans, since B has 20% more read beans, and .9x yellow, since B has 10% less yellow beans. So, B has 3.3x beans.
So B has 10% more beans than A.
Jinglander, do you know what is the OA?
B contains 20% more red beans than A. So lets say A has R red beans then B has 1.2R red beans. Also, A contains 10% more yellow beans than B. So, if B contains Y yellow beans then A contains 1.1Y yellow beans.
Jar A contains twice as many red beans as yellow.
Let say, A has x yellow beans that means there are 2x red beans. So A has 3x beans in total.
So, B has 2.4x read beans, since B has 20% more read beans, and .9x yellow, since B has 10% less yellow beans. So, B has 3.3x beans.
So B has 10% more beans than A.
Jinglander, do you know what is the OA?
