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hardworker_indian
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twixt
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Dookie
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twixt
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You're right dookie, i considered 30 games instead of 15...
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hardworker_indian
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Nope, anyone want to try? :no
Btw, this one was from Princeton Review.
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scoobee
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I think the table is showing partial standing, so the total number of games played as per the table is 26/2 = 13, I think. Of the 13, there are 4/2 ties or 2 ties. Extending it to 15 games and considering that team B which still has 2 unfinished games and a higher probability of tieing:-), now this is bit of a guess here. the prob for all games is 3/15 or 1/5 or 20%. I am not sure about the exact % and all refered to in the question :-).

So, my vote is for 20%.
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ice t
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i also vote for 20 % as there would have to be 15 total games played. before the last two games are played there were 2 ties (4 teams with a tie in their record). This leaves the following tie totals as possibilities:

2/15, 3/15, 4/15

3/15=20 %
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gmatace
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This problem can be resolved using a combination formula. Each win and each loss counts as one game. Each game results in a win and a loss or in a tie, with each tie getting counted twice. Total wins plus 1/2 ties tells us that 13 games have been played with 2 ending in a tie. If 2 more games are played, the possible outcomes - ties over total games are:

2/15, 3/15 and 4/15. Only 3/15 yields an exact percentage that correlates to one of the answers. All other possibilities are irrational numbers that cannot be give an exact %.



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