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Bunuel
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make a baseline for comparison -

a=3sqrt(7) = sqrt(63)
b=2sqrt(15) = sqrt(60)
c=5sqrt(13)/sqrt(5) = sqrt(65)
d=39/5 less than 8 but almost equal to it

Then sorting answers in an order
we now know that
b<a,d<c

we have to figure out the position of a and d.

Find out the value of a by long division method and the compare

b<d<a<c
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utin
any quick way to solve this plsss...???


Nothing quicker than what's been described in the previous responses

Posted from my mobile device
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Asked: Which of the following statements is true?


A. \(3\sqrt{7}<2\sqrt{15}<\frac{5\sqrt{13}}{\sqrt{5}}<\frac{39}{5}\)
\(\sqrt{63}<\sqrt{60}<\sqrt{65}<7.8\): FALSE

B. \(2\sqrt{15}<\frac{39}{5}<3\sqrt{7}<\frac{5\sqrt{13}}{\sqrt{5}}\)
\(\sqrt{60}<7.8<\sqrt{63}<\sqrt{65}\): TRUE

C. \(2\sqrt{15}<3\sqrt{7}<\frac{39}{5}<\frac{5\sqrt{13}}{\sqrt{5}}\)
\(\sqrt{60}<\sqrt{63}<7.8<\sqrt{65}\) : FALSE

D. \(2\sqrt{15}<3\sqrt{7}<\frac{5\sqrt{13}}{\sqrt{5}}<\frac{39}{5}\)
\(\sqrt{60}<\sqrt{63}<\sqrt{65}<7.8\) : FALSE

E. \(2\sqrt{15}<\frac{5\sqrt{13}}{\sqrt{5}}<3\sqrt{7}<\frac{39}{5}\)
\(\sqrt{60}<sqrt{65}<\sqrt{63}<7.8}\) : FALSE

IMO B
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just square them all and then they are easier to compare.
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