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jananijayakumar
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If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the 28 Aug 2010, 10:21
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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55% (hard)

Question Stats:

73% (02:04) correct 27% (03:55) wrong based on 15 sessions

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If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the area of trapezoid BEDC? (Figure attached)

A) 12
B) 18
C) 24
D) 30
E) 48

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-be-cd-and-bc-ab-3-ae-4-and-cd-10-what-is-127060.html

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Bunuel
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If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the 28 Aug 2010, 11:10
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jananijayakumar
If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the area of trapezoid BEDC? (Figure attached)
A) 12
B) 18
C) 24
D) 30
E) 48
Attachment:
Untitled.jpg
Show more

I guess it's BE||CD (BE is parallel to CD).

Triangles ABE and ACD are similar (they share the same angle CAD and also as BE is parallel to CD then angles by BE and CD are equal, so all 3 angles of these triangles are equal so they are similar triangles).

Property of similar triangles: ratio of corresponding sides are the same: \(\frac{AB}{AC}=\frac{BE}{CD}\) --> \(\frac{3}{6}=\frac{BE}{10}\) --> \(BE=5\) and \(AD=2AE=8\).

So in triangle ABE sides are \(AB=3\), \(AE=4\) and \(BE=5\): we have 3-4-5 right triangle ABE (with right angle CAD, as hypotenuse is \(BE=5\)) and 6-8-10 right angle triangle ACD.

Now, the \(area_{BEDC}=area_{ACD}-area_{ABE}\) --> \(area_{BEDC}=\frac{6*8}{2}-\frac{3*4}{2}=18\).

Answer: B.

Hope it's clear.
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If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the 28 Aug 2010, 12:30
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Bunuel - In this case it turned out to be a rt angled triangle so the area calc was easy.. Lets say the bigger triangle were 5 7 9 in sides and the smaller was correspondingly half in size inside of it.. In that case, what would be the easiest way to calculate the trapezium area.. I guess does GMAT require us to remember the formula of the area of a triangle (not the .5 base height) but the one with the sides? Is there an easy way to calculate the area where the sides are given for any triangle?
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If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the 28 Aug 2010, 12:48
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mainhoon
Bunuel - In this case it turned out to be a rt angled triangle so the area calc was easy.. Lets say the bigger triangle were 5 7 9 in sides and the smaller was correspondingly half in size inside of it.. In that case, what would be the easiest way to calculate the trapezium area.. I guess does GMAT require us to remember the formula of the area of a triangle (not the .5 base height) but the one with the sides? Is there an easy way to calculate the area where the sides are given for any triangle?
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If it were not right triangle we could calculate the area of triangles with Heron's Formula (as we still would knew the lengths of all sides), though I've never seen a GMAT question requiring it.
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If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the 13 Sep 2010, 07:18
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Bunuel
jananijayakumar
If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the area of trapezoid BEDC? (Figure attached)
A) 12
B) 18
C) 24
D) 30
E) 48
Attachment:
Untitled.jpg

I guess it's BE||CD (BE is parallel to CD).

Triangles ABE and ACD are similar (they share the same angle CAD and also as BE is parallel to CD then angles by BE and CD are equal, so all 3 angles of these triangles are equal so they are similar triangles).

Property of similar triangles: ratio of corresponding sides are the same: \(\frac{AB}{AC}=\frac{BE}{CD}\) --> \(\frac{3}{6}=\frac{BE}{10}\) --> \(BE=5\) and \(AD=2AE=8\).

So in triangle ABE sides are \(AB=3\), \(AE=4\) and \(BE=5\): we have 3-4-5 right triangle ABE (with right angle CAD, as hypotenuse is \(BE=5\)) and 6-8-10 right angle triangle ACD.

Now, the \(area_{BEDC}=area_{ACD}-area_{ABE}\) --> \(area_{BEDC}=\frac{6*8}{2}-\frac{3*4}{2}=18\).

Answer: B.

Hope it's clear.
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Bunuel... If you say that
BC = AB = 3, AE = 4
then how can BE||CD (BE is parallel to CD) true. I am not able to visualize such a figure!!! :(
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If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the 13 Sep 2010, 08:42
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utin
Bunuel
jananijayakumar
If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the area of trapezoid BEDC? (Figure attached)
A) 12
B) 18
C) 24
D) 30
E) 48
Attachment:
Untitled.jpg

I guess it's BE||CD (BE is parallel to CD).

Triangles ABE and ACD are similar (they share the same angle CAD and also as BE is parallel to CD then angles by BE and CD are equal, so all 3 angles of these triangles are equal so they are similar triangles).

Property of similar triangles: ratio of corresponding sides are the same: \(\frac{AB}{AC}=\frac{BE}{CD}\) --> \(\frac{3}{6}=\frac{BE}{10}\) --> \(BE=5\) and \(AD=2AE=8\).

So in triangle ABE sides are \(AB=3\), \(AE=4\) and \(BE=5\): we have 3-4-5 right triangle ABE (with right angle CAD, as hypotenuse is \(BE=5\)) and 6-8-10 right angle triangle ACD.

Now, the \(area_{BEDC}=area_{ACD}-area_{ABE}\) --> \(area_{BEDC}=\frac{6*8}{2}-\frac{3*4}{2}=18\).

Answer: B.

Hope it's clear.

Bunuel... If you say that
BC = AB = 3, AE = 4
then how can BE||CD (BE is parallel to CD) true. I am not able to visualize such a figure!!! :(
Show more

Why not? Consider triangle CAD, where CA=6 and AD=8. Now draw midsegment BE of a triangle (a line segment joining the midpoints of two sides of a triangle). Properties of a midsegment:

• The midsegment is always parallel to the third side of the triangle.
• The midsegment is always half the length of the third side.

Check Triangles chapter of Math Book: math-triangles-87197.html

Hope it helps.
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If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the 18 Sep 2010, 08:11
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Thanks again Bunuel!!! I was thinking of one triangle in the attachment only...
didn't generalize...
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If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the 29 Nov 2010, 14:17
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If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the area of trapezoid BEDC?
a) 12
b) 18
c) 24
d) 30
e) 48

Source: Manhattan CAT Exam

Solution to follow.

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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
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